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Leto [7]
3 years ago
11

True or False? Nitrogen can get back into the atmosphere when dead plants and animals are decomposed by bacteria. The bacteria b

reak down the larger molecules into smaller ones including nitrates, ammonia, and ultimately N2. True or Fralse
Chemistry
2 answers:
Readme [11.4K]3 years ago
6 0

Answer: True

Explanation:

AleksandrR [38]3 years ago
5 0

Answer:

idkkkkkkkklkllkkkkkkkkkkkkkk

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What do you think would be the most challenging part of investigating a fire or explosion crime scene? Why?
Lena [83]

Answer:

I think finding the source of the fire would be the most difficult aspect seeing as though the fire would have burned any evidence

Explanation:

7 0
3 years ago
What are the coefficients for the reaction _Cl2O5 + _H2O → _HClO3 once it is balanced?
muminat

Answer:

1, 1, 2

Explanation:

5 0
3 years ago
Read 2 more answers
Which of the following is an example of a phase?
Zielflug [23.3K]

Answer:

An example of a phase is the final part of a multiple part landscaping project. An example of a phase is when you can the various shapes of the moon. An example of phase is a period of time during which you are a teenager when you fight with your parents all the time.

Explanation:

7 0
3 years ago
How many moles does the mass quantity 130g of H2O have?
SVETLANKA909090 [29]
It has 7.22 moles.... mole =mass/molar mass
molar mass of H2O=18
130/18=mole
7 0
3 years ago
Consider the balanced reaction: 4Ga(s) + 3O2(g)⟶ 2Ga2O3(s)
Paha777 [63]

First we need to find the number of moles that 43.9g of gallium metal is. We can do this by finding the molar weight of gallium and cross-multiplying to cancel out units:


\frac{1mole}{69.723g}*\frac{43.9g}{1}=0.63mol_{Ga}


So we are dealing with 0.63 moles of gallium metal.


We can take from the balanced equation that 4 moles of gallium metal will react completely with 3 moles of oxygen gas. We can take this ratio and make a proportion to find the amount of oxygen gas, in moles, that will react completely with 0.63 moles of gallium metal:


\frac{4moles_{Ga}}{3moles_{O_{2}}} =\frac{0.63moles_{Ga}}{xmoles_{O_{2}}}


Cross multiply and solve for x:


4x=1.89


x=0.47moles_{O{2}}


So now we know that 0.47 moles of oxygen gas will react with 43.9g of gallium metal.

5 0
3 years ago
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