Explanation:
The given data is as follows.
Solvent 1 = benzene,          Solvent 2 = water
   = 2.7,
 = 2.7,          = 100 mL
 = 100 mL
 = 10 mL,       weight of compound = 1 g
 = 10 mL,       weight of compound = 1 g
        Extract = 3
Therefore, calculate the fraction remaining as follows.
                   ![f_{n} = [1 + K_{p}(\frac{V_{S_{2}}}{V_{S_{1}}})]^{-n}](https://tex.z-dn.net/?f=f_%7Bn%7D%20%3D%20%5B1%20%2B%20K_%7Bp%7D%28%5Cfrac%7BV_%7BS_%7B2%7D%7D%7D%7BV_%7BS_%7B1%7D%7D%7D%29%5D%5E%7B-n%7D)
                                   = ![[1 + 2.7(\frac{100}{10})]^{-3}](https://tex.z-dn.net/?f=%5B1%20%2B%202.7%28%5Cfrac%7B100%7D%7B10%7D%29%5D%5E%7B-3%7D)
                                   = 
                                   = 
Hence, weight of compound to be extracted = weight of compound - fraction remaining
                                   = 1 - 
                                   = 0.00001
or,                               = 
Thus, we can conclude that weight of compound that could be extracted is  .
.
 
        
                    
             
        
        
        
Answer:
I'm not sure if this right because i've only taken one year of Chemistry but the answer I got was
A. 24 g
 
        
             
        
        
        
Answer:
2.93g
Explanation:first, let us calculate the number of mole of NaCl present in the solution. This is illustrated below:
Molarity = 0.5M
Volume = 100cm^3 = 100/1000 = 0.1L
Mole =?
Molarity = mole /Volume
Mole = Molarity x Volume
Mole of NaCl = 0.5 x 0.1 = 0.05mole
Now we can obtain the mass of NaCl as follows:
Molar Mass of NaCl = 23 + 35.5 = 58.5g/mol
Mole of NaCl = 0.05mol
Mass of NaCl =?
Mass = number of mole x molar Mass
Mass of NaCl = 0.05 x 58.5
Mass of NaCl = 2.93g
 
        
             
        
        
        
Answer:
The answer is Near The Ocean Ridges. 
 
        
             
        
        
        
HCl(aq) + KOH(s) --> KCl(aq) + H2O(l)