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FromTheMoon [43]
3 years ago
13

there are several ways to express solution concentration dilute concentrated ppm molarity molality normality all of these have o

ne thing in common they describe the ​

Chemistry
2 answers:
klio [65]3 years ago
4 0

B: quantity of solute with a specific volome of solvent.

Have a Nice Day :)

Rina8888 [55]3 years ago
4 0

Answer: quantity of solute dissolved in a given quantity of solvent

Explanation:-

Dilute : is defined as a solution in which amount of solvent is more than the amount of solute.

Concentrated: is defined as a solution in which amount of solute is more than the amount of solvent.

ppm: ppm is defined as the concentration when 1 part of the solute is  dissolved per 1 million of the solution.

Molarity: Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Molality : Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

Normality: Normality of a solution is defined as the number of ram equivalents of solute dissolved per Liter of the solution.

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Sodium hydroxide reacts with aluminum and water to produce hydrogen gas: 2 Al(s) + 2 NaOH(aq) + 6 H2O(l) → 2 NaAl(OH)4(aq) + 3 H
lianna [129]

Answer:

The mass of hydrogen gas formed is 0.205 grams

Explanation:

<u>Step 1:</u> Data given

Mass of 1.83 grams of Al

Mass of NaOH = 4.30 grams

Molar mass of Al = 26.98 g/mol

Molar mass of NaOH = 40 g/mol

<u>Step 2:</u> The balanced equation:

2 Al(s) + 2 NaOH(aq) + 6 H2O(l) → 2 NaAl(OH)4(aq) + 3 H2(g)

<u>Step 3:</u> Calculate moles of Al

Moles Al = mass Al / Molar mass Al

Moles Al = 1.83 grams / 26.98 g/mol

Moles Al = 0.0678 moles

<u>Step 4:</u> Calculate moles of NaOH

Moles NaOH = 4.30 grams / 40 g/mol

Moles NaOH = 0.1075 moles

<u>Step 5</u>: Calculate limiting reactant

For 2 moles of Al, we need 2 moles of NaOH

Aluminium is the limiting reactant. It will completely be consumed ( 0.0678 moles)

NaOH is in excess. There will react 0.0678 moles

There will remain 0.1075 - 0.0678 = 0.0397 moles

<u>Step 6</u>: Calculate moles of hydrogen

For 2 moles of Al, we need 2 moles of NaOH, to produce 3 moles of hydrogen

For 0.0678 moles of Al, there is produced 0.0678 *3/2 = 0.1017 moles of H2

<u>Step 7</u>: Calculate mass of H2

Mass of H2 = Moles H2 * Molar mass of H2

Mass of H2 = 0.1017 moles * 2.02 g/mol

Mass of H2 = 0.205 grams

The mass of hydrogen gas formed is 0.205 grams

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