Ask question

Ask question

All categories

4 years ago

10

100 POINTS ANSWER HURRY

2 answers:

mylen [45]4 years ago

8 0

Not all mixtures can be classified as solutions because C. not all mixtures have solutes and solvents.

You can answer this using the process of elimination. You know the answer cannot be A. because compounds are mixtures. It cannot be B. solutions are homogenous, so it wouldn't matter if the mixture was heterogeneous or not. It cannot be D. because mixtures have to be 2 or more substances.

prisoha [69]4 years ago

7 0

C. Not all mixtures have solutes and solvents

You might be interested in

A 4.000 g sample of an unknown metal, M, was completely burned in excess O2 to yield 0.02225 mol of the metal oxide, M2O3. What

Solnce55 [7]

4X + 3O₂ = 2X₂O₃

n(X₂O₃)=0.02225 mol
m(X)=4.000 g
x - the molar mass of metal

m(X)/4x=n(X₂O₃)/2

x=m(X)/{2n(X₂O₃)}

x=4.000/{2*0.02225)=89.89 g/mol

X=Y (yttrium)

7 0

4 years ago

Determine the specific heat of a 70 g sample of material that absorbed 96 J as it was heated from 293 K to 313 K

Damm [24]

This problem is providing us with the mass (70 g), absorbed heat (96 J) and initial and final temperatures (293 K and 313 K, respectively) so the specific heat of the material is required and found to be 0.0686 J/(g*K) as shown below:

<h3>Calorimetry:</h3>

In chemistry, we can go over calorimetry by writing the following relationship among heat, mass, specific heat and temperature change:

$Q=mC(T_f-T_i)$

Thus, one can get the specific heat by solving for C in the previous equation:

$C=\frac{Q}{m(T_f-T_i)}$

Hence, we can plug in the given data to obtain:

$C=\frac{96J}{70g(313K-293K)}\\ \\C=0.0686\frac{J}{g*K}$

Learn more about calorimetry: brainly.com/question/1407669

5 0

2 years ago

Consider the reaction. 2c(s,graphite) h2= c2h2(g) Based on the equation and the information in the table, what is the enthalpy o

xxTIMURxx [149]

<h3>The enthalpy of the reaction : C.226.73 kJ</h3><h3>Further explanation</h3>

Delta H reaction (ΔH) is the amount of heat change between the system and its environment

(ΔH) can be positive (endothermic = requires heat) or negative (exothermic = releasing heat)

The change in enthalpy in the formation of 1 mole of the elements is called enthalpy of formation

Delta H reaction (ΔH) is the difference between product enthalpy and reactant enthalpy (Hp-Hr)

Reaction :

2C + H2 -> C2H2

(ΔH) reaction = (ΔH) product - (ΔH) reactants

(ΔH) reaction = (ΔH) C2H2 - ((ΔH) C + (ΔH) H2)

for free element (ΔH) it has zero value, so (ΔH) C and (ΔH) H2 have zero value

From the available data: Hf (kJ / mol) C2 H2 (g)= 226.73

then

(ΔH) reaction = ΔH) C2H2 - ((ΔH) C + (ΔH) H2)

(ΔH) reaction = 226.73 - (0 + 0)

(ΔH) reaction = 226.73 (answer C)

<h3>Learn more</h3>

(ΔH) reaction

brainly.com/question/1889660

Keywords : (ΔH) reaction, C2H2

8 0

3 years ago

Read 2 more answers

What's the difference between a mole of propane and a gram of propane? <br>

kobusy [5.1K]

B. A gram would have a lot more molecules of propane than a mole

5 0

3 years ago

If the diver were to ascend to the surface (where the pressure is 1.0 atm) while holding her breath, to what volume would the ai

sertanlavr [38]

Im not 100% sure put i think 6.0

5 0

4 years ago