All categories

3 years ago

100 POINTS ANSWER HURRY

2 answers:

8 0

Not all mixtures can be classified as solutions because C. not all mixtures have solutes and solvents.

You can answer this using the process of elimination. You know the answer cannot be A. because compounds are mixtures. It cannot be B. solutions are homogenous, so it wouldn't matter if the mixture was heterogeneous or not. It cannot be D. because mixtures have to be 2 or more substances.

prisoha [69]3 years ago

7 0

C. Not all mixtures have solutes and solvents

You might be interested in

Oliver needs to standardize a base solution by titration with an acid solution of known concentration. He finds the volume of th

Olin [163]

Write a balance equation for the reaction between the analyte and the titrant.
Calculate the # of moles of titrant using the volume of titrant required and the concentration of titrant.
Calculate the # of moles of analyte using the stoichiometric coefficients of the equation.
Calculate the concentration of the analyte using the number or moles of analyte and the volume of analyte titrated.

7 0

2 years ago

Maya prepared 0.50 liters of a solution by dissolving 2.0 moles of an unknown compound in water. What is the molarity of the sol

Elena-2011 [213]

Answer:

4 M

Explanation:

Molarity can be represented by the following ratio:

Molarity = moles / volume (L)

Since you have been given both the mass and volume, you can plug the values into the equation and solve for molarity.

Molarity = moles / volumes

Molarity = 2.0 moles / 0.50 L

Molarity = 4 M

6 0

1 year ago

The estimated heat of vaporization of diethyl ether using the Chen's rule is A. 29.7 KJ/mol B. 33.5 KJ/mol C. 26.4 KJ/mol D. 36.

Brums [2.3K]

Answer:

C. 26.4 kJ/mol

Explanation:

The Chen's rule for the calculation of heat of vaporization is shown below:

$\Delta H_v=RT_b\left [ \frac{3.974\left ( \frac{T_b}{T_c} \right )-3.958+1.555lnP_c}{1.07-\left ( \frac{T_b}{T_c} \right )} \right ]$

Where,

$\Delta H_v$ is the Heat of vaoprization (J/mol)

$T_b$ is the normal boiling point of the gas (K)

$T_c$ is the Critical temperature of the gas (K)

$P_c$ is the Critical pressure of the gas (bar)

R is the gas constant (8.314 J/Kmol)

For diethyl ether:

$T_b=307.4\ K$

$T_c=466.7\ K$

$P_c=36.4\ bar$

Applying the above equation to find heat of vaporization as:

$\Delta H_v=8.314\times307.4 \left [ \frac{3.974\left ( \frac{307.4}{466.7} \right )-3.958+1.555ln36.4}{1.07-\left ( \frac{307.4}{466.7} \right )} \right ]$

$\Delta H_v=26400 J/mol$

The conversion of J into kJ is shown below:

1 J = 10⁻³ kJ

Thus,

$\Delta H_v=26.4 kJ/mol$

<u>Option C is correct</u>

6 0

3 years ago

What is the definition of Axis of rotation

il63 [147K]

Answer: an invisible line around which an object rotates, or spins.

Explanation: //Give thanks(and or Brainliest) if helpful (≧▽≦)//

6 0

2 years ago

What volume of water has the same mass as 9.0m3 of ethyl alcohol?

Triss [41]

This question requires the knowledge of density.

The density of ethyl alcohol = 789 kg m⁻³
The density of water = 1000 kg m⁻³

Density = Mass / Volume

By applying ethyl alcohol,
789 kg m⁻³ = Mass / 0.9 m³
Mass = 710.1 kg
hence the mass of 0.9 m³ ethyl alcohol is 710.1 kg.

Then by applying water,
1000 kg m⁻³ = 710.1 kg / Volume
Volume = 0.7101 m³
= 0.7 m³
hence the equal water volume is 0.7 m³

8 0

3 years ago