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3 years ago

100 POINTS ANSWER HURRY

2 answers:

8 0

Not all mixtures can be classified as solutions because C. not all mixtures have solutes and solvents.

You can answer this using the process of elimination. You know the answer cannot be A. because compounds are mixtures. It cannot be B. solutions are homogenous, so it wouldn't matter if the mixture was heterogeneous or not. It cannot be D. because mixtures have to be 2 or more substances.

prisoha [69]3 years ago

7 0

C. Not all mixtures have solutes and solvents

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Identify the functional groups present in each molecule.

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3 years ago

Using the formula M1V1 = M2V2 , how many milliliters of a 2. 50 M hydrochloric acid solution is required to make 100. 0 mL of a

gladu [14]

Dilution of the solution can be calculated by the formula of the molarity and volume. The initial volume of 2.50 M solution was 30 mL.

<h3>What is the relationship between molar concentration and dilution?</h3>

Molar concentration or the dilution factor is in an inverse relationship and with an increase in the dilution, the molarity of the solution decreases.

Given,

Initial molarity = 2.50 M

initial volume = ?

Final molarity = 0.750 M

Final volume = 100.0 ml

Substituting values in the formula:

$\begin{aligned}\rm V_{1} &= \rm \dfrac{M_{2}V_{2}}{M_{1}}\\\\&= \dfrac{0.750 \times 100}{2.50}\\\\&= 30 \;\rm mL\end{aligned}$

Therefore, 30 mL was the initial volume of the solution before it was diluted.

Learn more about dilution here:

brainly.com/question/26896011

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2 years ago