No, the car travels 1 metre in 5s at the start which is 0.2m/s, while the second meter it travels one metre in 8 seconds which is 0.125 m/s, the speed changes therefore it is not constant during the two metres the car travels
Answer:
60°
Explanation:
The scalar product of two vectors with an angle ∅ between them is defined as:
Solving for angle ∅:
The answer is A.
Sy = 1650 x sin30.5 = 837.4 m toward south
Sx = 1650 x cos30.5 = 1421.7 m toward east
Weight / g = mass 300N/9.8m/s^2= mass 30.6kg
Answer:
13950kg
Explanation:
If we make the system both railroad cars, we know that the momentum of the whole system doesn't change because the forces are internal.
Let a be the mass of the second car.
The original momentum is 9300*15 kg*m/s+ a*0 kg*m/s = 139500 kg*m/s
After sticking together, the momentum is (9300+a)kg*6m/s, which should be equal to 139500 kg*m/s
Therefore (9300+a)*6 = 139500
9300+a = 23250
a = 13950 kg
