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FinnZ [79.3K]
3 years ago
14

1. A student tried to solve the following problem by selecting the tile as shown. What, if anything, did the student do wrong?

Chemistry
1 answer:
slega [8]3 years ago
6 0

Answer:

B. The student chose the correct tile, but needs to flip the tile to make the units cancel

Explanation:

Based on the reaction:

2AgNO₃(aq) + Cu(s) → 2Ag(s) + Cu(NO₃)₂ (aq)

<em>2 moles of AgNO₃ react per mole of Cu producing 2 moles of Ag and 1 mole of Cu(NO₃)₂</em>

Thus, if you want to produce 6.75moles of Cu(NO₃)₂ you need:

6.75moles of Cu(NO_3)_2  \frac{2 mol AgNO_3 }{1 mol Cu(NO_3)_2} = 13.50 moles of AgNO₃ are needed

Thus, if you analize the tile shown by the student:

<em>B. The student chose the correct tile, but needs to flip the tile to make the units cancel</em>

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Calculate the number of atoms per unit cell in each type of cubic unit cell. Enter three integers separated by commas (e.g., 1,2
agasfer [191]

Answer:

1, 2, 4

Explanation:

The primitive cubic unit cell has eight corners, and each corner is shared with 8 cubic unit cells. Therefore since we have one atom at each corner, we will have:

8 corner x  1 atom/8 corner = 1 atom

There is then the equivalent of one atom per unit cell in the primitive cubic cell.

For the body-centered cubic unit cell, we have 8 corners again shared each by 8 lattices as in the simple cubic plus we have one atom  in the center of the cubic lattice. Therefore, the number of atoms in the body -centerd unit cell is two:

8 corner x 1 atom/8 corner = 1 atom

                      +

1 atom in the center

= 2 atoms/ unit cel

For the face-centerd cubic again we have 8 atoms in the corners shared by 8 lattices, plus 1 atom in each of the faces shared by two unit cells:

8 corner x 1/8 atom/corner + 6 faces x 1 atom/face = 4 atoms/unit cell

4 0
4 years ago
Pleas help me i have to submit homework i hour<br> i will mark brainliest
steposvetlana [31]

Answer:

I can help

Explanation:

++++++++++++++++++++++++++++

6 0
3 years ago
Identify the conjugate acid/base pairs in each of the following equations:
Valentin [98]

Answer:

(a) Pair 1: H₂S and HS⁻

    Pair 2: NH₃ and NH₄⁺

(b) Pair 1: HSO₄⁻ and SO₄⁻

    Pair 2: NH₃ and NH₄⁺

(c) Pair 1: HBr and Br⁻

    Pair 2: CH₃O⁻ and CH₃OH

(d)  Pair 1: HNO₃ and NO₃⁻

     Pair 2: H₃O⁺

Explanation:

When an acid loses its proton (H⁺), a conjugate base is produced.

When a base accepts a proton (H⁺), it forms a conjugate acid.

(a) H₂S is an acid. When it loses a proton, it forms the conjugate base HS⁻.

    NH₃ is a base. When NH₃ gains a proton, it forms the conjugate acid NH₄⁺

(b) The acid HSO₄⁻ loses a H⁺ ion and forms the conjugate base SO₄²⁻.

     The base NH₃ accepts a H⁺ ion to form the conjugate acid NH₄⁺.

(c) HBr is an acid. When loses the H⁺ ion, it forms the conjugate base Br⁻.

   CH₃O⁻ accepts a H⁺ ion to form the conjugate acid CH₃OH.

(d) HNO₃ loses a proton to form the conjugate base NO₃⁻.

    H₂O gains a proton to form the conjugate acid H₃O⁺.

6 0
3 years ago
a block of iron has the dimensions of 3.00 cm x 3.00 cm x 3.00 cm. it has a mass of 213 g. what is its density? a. 638 g/cm3 b.
Juliette [100K]
Volume = 3 cm × 3cm × 3cm
             =  27 cm ³

Mass  =  213 g

Density  =  \frac{MASS}{VOLUME}
 
              = <span>\frac{213 g}{27 cm ^{3} }
</span> 
<span>              =  7.89 g / cm³

Thus answer is D.</span>
8 0
3 years ago
Read 2 more answers
Name the organic molecule
tekilochka [14]

Answer:

hydrocarbons are the answer

6 0
3 years ago
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