a) No, R is not a subset of T that is NOT ALL the elements of R can be found in T. For R ⊆ T, it means that ALL the element of R can be found in T which is false in this case.
b) Yes, T is a subset of R that is ALL the element of T can be found in T since all the elements in both sets are all even. For T ⊆ R, it means that ALL the element of T can be found in R
c) No, T is not a subset of S that is NOT ALL the elements of T can be found in S. For T ⊆ S, it means that ALL the element of T can be found in S which is false in this case.
Let l and l-6 be the length and width, respectively, of the rectangle. Then: l(l-6)=40 l²-6l-40=0 (l-10)(l+4)=0 l=10,-4 The rectangle is 10" by 4". ☺☺☺☺