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3 years ago

Define what is retention ratio

Mathematics

1 answer:

ycow [4]3 years ago

4 0

Answer:

Retention ratio indicates the percentage of a company's earnings that are not paid out in dividends but credited to retained earnings. It is the opposite of the dividend payout ratio, so that also called the retention rate.

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Select two choices that are true about the function f(x)=23x+14/x

WINSTONCH [101]

Answer:

There is an asymptote at x = 0

There is an asymptote at y = 23

Step-by-step explanation:

Given the function:

(23x+14)/x

Vertical asymptote is gotten by equating the denominator to zero

Since the denominator is x, hence the vertical asymptote is at x = 0. This shows that there is an asymptote at x = 0

Also for the horizontal asymptote, we will take the ratio of the coefficient of the variables in the numerator and denominator

Coefficient of x at the numerator = 23

Coefficient of x at the denominator = 1

Ratio = 23/1 = 23

This means that there is an asymptote at y = 23

8 0

3 years ago

Which of these is a binomial? O A. x + 2y2 - 7 O B. ab O C. 5xy O D. 2x3 - 7y3

Lemur [1.5K]

Answer:

Step-by-step explanation:

2 terms

8 0

3 years ago

Kate's swim coach informs her that she only has 35% of her workout left. Kate has swum 26 laps so far.

pentagon [3]

Kate needs to swim 40 laps to come complete 66 laps

7 0

3 years ago

[4]

Tanya [424]

Answer:

Angle ACD = 38°

Step-by-step explanation:

The full, correct question is presented the attached image to this solution.

Given

Point O is the centre if the circle

Points A, B, C and D are points on the circle

Angle AOB = 140°

Angle OAC = 14°

Angle AOB = 2 × (Angle ACB) [angle subtended at the centre of the circle is twice the angle subtended at the circumference of the circle)

140° = 2 × (Angle ACB)

Angle ACB = (140°/2) = 70°

(Angle AOB) + (Angle OAB) + (Angle ABO) = 180° [sun of angles in a triangle is 180°]

But Angle OAB = Angle ABO = a [base angles of an iscosceles triangle are equal since OA and OB are both radii for the circle O)

(Angle AOB) + (Angle OAB) + (Angle ABO) = 180°

140° + a + a = 180°

2a = 40°

a = (40/2) = 20°

Angle OAB = Angle ABO = 20°

Angle CAB = (Angle OAC) + (Angle OAB) = 14° + 20° = 34°

Triangle ADC is an iscosceles triangle, hence,

Angle DAC = Angle ACD = x [base angles of an iscosceles triangle are equal]

But

(Angle DCB) + (Angle DAB) = 180° [Opposite angles of a cyclic quadilateral (a quadilateral inscribed in a circle) sum up to give 180°]

Angle DCB = (Angle DCA) + (Angle ACB) = (x + 70°)

Angle DAB = (Angle DAC) + (Angle CAB) = (x + 34°)

(Angle DCB) + (Angle DAB) = 180°

(x + 70°) + (x + 34°) = 180°

2x + 104° = 180°

2x = 180° - 104° = 76°

x = (76°/2) = 38°

Angle DAC = Angle ACD = 38°

Angle ACD = 38°

Hope this Helps!!!

7 0

3 years ago

Let f be a differentiable function such that f(3)=15, f(6)=3, f ' (3)= -8, and f ' (6)= -2. The function g is differentiable and

Ray Of Light [21]

Answer:

A. $g'(3)=-\frac{1}{2}$

Step-by-step explanation:

We have been given that f be a differentiable function such that $f(3)=15$ , $f(6)=3$ , $f'(3)= -8$ , and $f'(6)= -2$ . The function g is differentiable and $g(x)= f^{-1} (x)$ for all x.