Answer: The rate = 8.5 ft/h
Step-by-step explanation:
Since we are going to need to differentiate to find the rate of change of θ we need to express it in radians rather than degrees.
Therefore, 15 degree per hour will be expressed as
15° × π/180 = 0.2618rad/hour
Using trigonometry function to find Ø
Tan Ø = 40/30 = 1.333
Ø = 53 degree
Convert it to radian
Ø = 0.93 rad
The changing at a rate of 15o per hour will be
Rate = radian/ time
0.2618 = (0.93 -0)/t
t = 0.93/0.2618
t = 3.5 hours
The rate of change in the length of the shadow at that same time will be:
Rate = 30/3.5 = 8.5 ft/ hour
Answer:
-3, 7
Step-by-step explanation:
EG = 5, so the distance between E and G is five.
G can be 5 units to the right of E:
2 + 5 = 7
G has coordinate 7.
G can be 5 units to the left of E:
2 - 5 = -3
G has coordinate -3.
Answer: -3, 7
Answer:
11
Step-by-step explanation:
4, 9, 16, 25, 36, 49, 64, 81, 100, 121
Answer: 13 months
Step-by-step explanation:
80 ÷ 6 = 13
Answer:
<h3>
ln (e^2 + 1) - (e+ 1)</h3>
Step-by-step explanation:
Given f(x) = ln and g(x) = e^x + 1 to get f(g(2))-g(f(e)), we need to first find the composite function f(g(x)) and g(f(x)).
For f(g(x));
f(g(x)) = f(e^x + 1)
substitute x for e^x + 1 in f(x)
f(g(x)) = ln (e^x + 1)
f(g(2)) = ln (e^2 + 1)
For g(f(x));
g(f(x)) = g(ln x)
substitute x for ln x in g(x)
g(f(x)) = e^lnx + 1
g(f(x)) = x+1
g(f(e)) = e+1
f(g(2))-g(f(e)) = ln (e^2 + 1) - (e+ 1)
