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2 years ago

What is the inverse of the function f(x)= x +3

Mathematics

1 answer:

pshichka [43]2 years ago

5 0

Hello,

if f(x)=y=x+3

x=y+3==>y=x-3

f^(-1) (x)=x-3 is the inverse function of f(x).

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Please help me, I don't understand this-

Andreas93 [3]

Answer:

i think its J 5,000 pounds

Step-by-step explanation:

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2 years ago

Gabriella is x years old. Her sister, Felicia, is six years older than she is. Their mother is twice as old as Felicia. Their au

Yuri [45]

G = x
Felicia is Gabriella's age + 6
F = x + 6
Their mother is twice Felicia's age
M = 2(x + 6) or 2x + 12
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A = 2x + 12 + x = 3x + 12
3x + 12

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3 years ago

Dori spent 1/5 of her money on a toy boat and scuba goggles. The toy boat cost 2 times as much as the goggles. The toy boat cost

Korolek [52]

Answer:

Dori has $48 left.

Step-by-step explanation:

The boat costs twice as much as the goggles, divide 8 by 2 to find the price of the goggles. The price of the goggles is $4.

Add $8 and $4 to get $12. This is the total money Dori spent.

Since this is 1/5 of her money, multiply $12 by 5 to get $60. This is the money Dori had.

Subtract the $12 from the $60 to get $48. This is the money Dori has left.

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2 years ago

An office supply warehouse has large boxes of folders. Each box has 550 folders. How many folders are there in 23 boxes?

alexandr1967 [171]

Step-by-step explanation:

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3 0

2 years ago

PLEASE PLEASE HELP! Find the measure of APB^.

Whitepunk [10]

Answer:

65°

Step-by-step explanation:

Radii CA and CB are perpendicular to tangent lines AT and BT, so

$\angle CAT=\angle CBT=90^{\circ}$

Since angle BAT is equal to 65°, angle CAB has measure

$\angle CAB=90^{\circ}-65^{\circ}=25^{\circ}.$

Consider triangle ACB. This triangle is isosceles, because CA=CB as radii of the circle. Two angles adjacent to the base are congruent, thus

$\angle CBA=\angle CAB=25^{\circ}$

The sum of the measures of all interior angles in triangle is always 180°, so

$\angle CAB+\angle CBA+\angle ACB=180^{\circ}\\ \\25^{\circ}+25^{\circ}+\angle ACB=180^{\circ}\\ \\\angle ACB=130^{\circ}$

Angle ACB is central angle subtended on the minor arc AB, angle APB is inscribed angle subtended on the same minor arc AB. The measure of inscribed angle is half the measure of central angle subtended on the same arc, so

$x=\angle APB=\dfrac{1}{2}\cdot 130^{\circ}=65^{\circ}$

8 0

3 years ago