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3 years ago

1.36 km is how many cm

Mathematics

1 answer:

Taya2010 [7]3 years ago

5 0

Answer:

136000 cm

Step-by-step explanation:

I think it's helps you

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Solve this k/3+4-2k=-9k

o-na [289]

K/3 + 4 -2k = -9k
First you add 9k to both sides
k/3 + 4 -2k = -9k
 +9k +9k
k/3 + 4 + 7k = 0

Now subtract 4 from both sides
k/3 + 4 + 7k = 0
 -4 -4
k/3 + 7k = -4

Now multiply 3 by both sides
k/3 + 7k = -4
x3 x3 x3
k +21k = -12

Now add k + 21k
22k = -12

Now divide both sides by 22
22k = -12
----- -----
22 22
k = -6/11

3 0

3 years ago

2 over 3 plus 3 over 8

denis-greek [22]

Hello,

The answer to your question is....

2/3 + 3/8

= (2 × 8) + (3 × 3)

3 × 8

= 25/24 OR 1 1/24

Hope this helps!!!! Sorry I took so long :)

3 0

3 years ago

Find the area of the figure shown below and choose the appropriate results

sweet [91]

Answer:

sorry if im rong but im prety sure its d

Step-by-step explanation:

8 0

3 years ago

What is the mean absolute deviation for the data set?

erastova [34]

The answer is A 3.92

8 0

3 years ago

The prices of all college textbooks follow a bell-shaped distribution with a mean of $113 and a standard deviation of $12. Using

Soloha48 [4]

Step-by-step explanation:

In statistics, the empirical rule states that for a normally distributed random variable,

68.27% of the data lies within one standard deviation of the mean.

95.45% of the data lies within two standard deviations of the mean.

99.73% of the data lies within three standard deviations of the mean.

In mathematical notation, as shown in the figure below (for a standard normal distribution), the empirical rule is described as

$\Phi(\mu \ - \ \sigma \ \leq X \ \leq \mu \ + \ \sigma) \ = \ 0.6827 \qquad (4 \ \text{s.f.}) \\ \\ \\ \Phi(\mu \ - \ 2\sigma \ \leq X \ \leq \mu \ + \ 2\sigma) \ = \ 0.9545 \qquad (4 \ \text{s.f.}) \\ \\ \\ \Phi}(\mu \ - \ 3\sigma \ \leq X \ \leq \mu \ + \ 3\sigma) \ = \ 0.9973 \qquad (4 \ \text{s.f.})$

where the symbol $\Phi$ (the uppercase greek alphabet phi) is the cumulative density function of the normal distribution, $\mu$ is the mean and $\sigma$ is the standard deviation of the normal distribution defined as $N(\mu, \ \sigma)$ .

According to the empirical rule stated above, the interval that contains the prices of 99.7% of college textbooks for a normal distribution $N(113, \ 12)$ ,

$\Phi(113 \ - \ 3 \ \times \ 12 \ \leq \ X \ \leq \ 113 \ + \ 3 \ \times \ 12) \ = \ 0.9973 \\ \\ \\ \-\hspace{1.75cm} \Phi(113 \ - \ 36 \ \leq \ X \ \leq \ 113 \ + \ 36) \ = \ 0.9973 \\ \\ \\ \-\hspace{3.95cm} \Phi(77 \ \leq \ X \ \leq \ 149) \ = \ 0.9973$

Therefore, the price of 99.7% of college textbooks falls inclusively between $77 and $149.

5 0

2 years ago