Answer : The concentration of at equilibrium is, 0.244 M, 0.122 M and 1.267 M respectively.
Explanation :
The given chemical reaction is:
Initial conc. 0.439 0.317 0.877
At eqm. (0.439-x) (0.317-x) (0.877+2x)
As we are given:
The expression for equilibrium constant is:
Now put all the given values in this expression, we get:
x = 0.195 and x = 0.690
We are neglecting the value of x = 0.690 because equilibrium concentration can not be more than initial concentration.
Thus, the value of x = 0.195 M
The concentration of at equilibrium = (0.439-x) = (0.439-0.195) = 0.244 M
The concentration of at equilibrium = (0.317-x) = (0.317-0.195) = 0.122 M
The concentration of at equilibrium = (0.877+2x) = (0.877+2\times 0.195) = 1.267 M