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Murrr4er [49]
3 years ago
5

Balance this equation, please.

Chemistry
1 answer:
Digiron [165]3 years ago
7 0

Answer:3Li+YbCl3=Yb +3LiCl

Explanation:as there are three cl in the first one so to balance them we will put 3before LiCl in order to make Cl balanced now there are 3 Li also so put before Li 3 making it also balanced Yb is balanced already

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Which type of reaction always has an element and a compound as reactants?
ladessa [460]

Answer:

B. single-replacement

Explanation:

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Is there something else that goes along with this?
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Dinitrogentetraoxide partially decomposes into nitrogen dioxide. A 1.00-L flask is charged with 0.0400 mol of N2O4. At equilibri
artcher [175]

Answer:

Keq=0.866

Explanation:

Hello,

In this case, the undergone chemical reaction is:

N_2O_42NO_2

In such a way, since 0.0055 mol of N₂O₄ remains in the flask, one infers that the reacted amount (x) was:

x=0.04mol-0.0055mol=0.0345mol

In addition, the produced amount of NO₂ is:

2*0.0345mol=0.069mol

Finally, considering the flask's volume, the equilibrium constant is then computed as follows:

Keq=\frac{(2*0.0345M)^2}{0.0055M}=0.866

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6 0
3 years ago
Why is the vapor pressure of a warm lake higher than the vapor pressure of a cold lake? A. Warm water has a greater heat of vapo
Naya [18.7K]

Answer : The correct option is B.

Explanation :

The temperature of the warm water is higher than the cold water. That means as the temperature of warm water increases, the kinetic energy of the warm water molecule also increases.

As the kinetic energy of the warm water molecule increases, the number of molecules conversion into a vapor also increases (i.e, quick evaporation), thereby increasing the vapor pressure of warm water.

Hence, the correct answer is, (B) Warm water evaporates more quickly.

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3 years ago
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A laboratory analysis of a 100 g sample finds it is composed of 1.8 g hydrogen, 56.1 g sulfur, and 42.1 g oxygen. What is its em
Neporo4naja [7]

Answer: The empirical formula is H_2S_2O_3

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mas of H = 1.8 g

Mass of S = 56.1 g

Mass of O = 42.1 g

Step 1 : convert given masses into moles.

Moles of H =\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{1.8g}{1g/mole}=1.8moles

Mass of S =\frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{56.1g}{32g/mole}=1.8moles

Moles of O=\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{42.1g}{16g/mole}=2.6moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For H = \frac{1.8}{1.8}=1

For S = \frac{1.8}{1.8}=1

For O =\frac{2.6}{1.8}=1.5

Converting to whole number ratios

The ratio of H: S: O= 2: 2: 3

Hence the empirical formula is H_2S_2O_3

7 0
3 years ago
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