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drek231 [11]
3 years ago
9

Which expression is equivalent to (a^6b^−3)1^/3 ?

Mathematics
2 answers:
Viefleur [7K]3 years ago
7 0

Answer:

a^2/b

Step-by-step explanation:

(a^6b^−3)1^/3


a^6 ^ 1/3  b ^ -3 ^ 1/3

using the power of power rule we can multiply the exponents

a ^ (6*1/3) b ^ (-3* 1/3)

a^ 2 b ^ -1

the negative exponent flips it from the numerator to the denominator

a^2* 1/ b^1

a^2/b

Misha Larkins [42]3 years ago
7 0

Answer:

Correct

Step-by-step explanation:

I just took the test

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3 years ago
Which equation represents the line that passes through the points (-3, 7) and (9,-1)? oy--3x+5 o y=-x-7 o y=zx-7 oy - 12 2x+5​
olchik [2.2K]

Answer:

The answer is

<h2>y =  -  \frac{2}{3} x + 5</h2>

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

To find the equation we must first find the slope of the line.

So the slope of the line using points (-3, 7) and (9,-1) is

<h3>m =  \frac{ - 1 - 7}{9 + 3}  =  -  \frac{8}{12}  =  -  \frac{2}{3}</h3>

Now we use the formula

<h3>y - y1 = m(x - x1)</h3>

where

m is the slope

( x1 , y1) is any of the points given

So the equation of the line using point

( - 3 , 7) and slope - 2/3 is

<h3>y - 7 =  -  \frac{2}{3} (x + 3) \\ y - 7 =  -  \frac{2}{3} x - 2 \\ y =  -  \frac{2}{3} x - 2 + 7</h3>

We have the final answer as

<h3>y =  -  \frac{2}{3} x + 5</h3>

Hope this helps you

5 0
3 years ago
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16,17,18

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