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Natasha_Volkova [10]
3 years ago
13

How much time would Simpson save by increasing his average velocity to 26m/s East?

Physics
1 answer:
igor_vitrenko [27]3 years ago
7 0

Answer:

8 minutes

Explanation:

Part of the question is missing. Complete question is:

<em>Simpson drives his car 144 km with an average velocity of 24 m/s toward the east. How much time would Simpson save by increasing his average velocity to 26m/s East?</em>

Solution:

First of all, we have to calculate the time it takes for Simpson to complete the drive moving at the initial velocity, 24 m/s. We can use the formula:

t=\frac{d}{v}

where

d=144 km = 1.44\cdot 10^5 m is the displacement

v=24 m/s is the velocity

Substituting,

t=\frac{1.44\cdot 10^5}{24}=6000 s = 100 min

While driving at 26 m/s, the time taken will be

t=\frac{1.44\cdot 10^5}{26}=5538 s=92 min

So, Simpson will save 8 minutes.

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A gas giant is a huge planet made of gases primarily hydrogen and helium. These gas giant planets include Jupiter, Saturn, Uranus, and Neptune.

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Give an example of something that is cyclic and non - cyclic
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 a clock .. and i guess a non functioning clock ?

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A car is moving at a constant speed of 100 miles per hour. how long does it take for the car to travel 200 miles.
Pepsi [2]

Answer:

d. 2 hours

Explanation:

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4 0
3 years ago
A ball of mass m on a string of length L is attached to a pivot. The ball is released from rest while the string is parallel to
mash [69]

Answer:

L/2

Explanation:

Neglect any air or other resistant, for the ball can wrap its string around the bar, it must rotate a full circle around the bar. This means the ball should be able to swing to the top position where it's directly above the bar. By the law of energy conservation, this happens when the ball is at the same level as where it's previously released vertically. It means the swinging radius around the bar must be at least half of the string length.

So the distance d between the bar and the pivot should be at least L/2

8 0
3 years ago
How much tension must a rope withstand if it is used to accelerate a 6526 kg car vertically upwards at 8.9 m/s^2?
ExtremeBDS [4]

Answer:

The value is T =  122036.2 \  N

Explanation:

From the question we are told that

     The mass of the car is  m  = 6526 \  kg

      The acceleration  is  a=  8.9 \  m/s^2

Generally the net force applied on the rope is mathematically represented as

          F_{net}   =  T -  W

Here W is the weight of the car which is evaluated as

         W =  m * g

=>      W =  6526  * 9.8

=>       W =  63954.8 \  N

Generally the net force can also be mathematically represented as

       F =  m * a

So

        m * a  =  T  -  63954.8

=>     6526  *  8.9 =  T  -  63954.8

=>      T =  122036.2 \  N

7 0
3 years ago
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