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Natasha_Volkova [10]
3 years ago
13

How much time would Simpson save by increasing his average velocity to 26m/s East?

Physics
1 answer:
igor_vitrenko [27]3 years ago
7 0

Answer:

8 minutes

Explanation:

Part of the question is missing. Complete question is:

<em>Simpson drives his car 144 km with an average velocity of 24 m/s toward the east. How much time would Simpson save by increasing his average velocity to 26m/s East?</em>

Solution:

First of all, we have to calculate the time it takes for Simpson to complete the drive moving at the initial velocity, 24 m/s. We can use the formula:

t=\frac{d}{v}

where

d=144 km = 1.44\cdot 10^5 m is the displacement

v=24 m/s is the velocity

Substituting,

t=\frac{1.44\cdot 10^5}{24}=6000 s = 100 min

While driving at 26 m/s, the time taken will be

t=\frac{1.44\cdot 10^5}{26}=5538 s=92 min

So, Simpson will save 8 minutes.

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Answer:

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2 years ago
You drive a car 1600 ft to the east, then 2500 ft to the north. The trip took 2.5 minutes. What was the magnitude of your averag
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Answer:

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Explanation:

Given data

Time t=2.5 minutes=150 seconds

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To find

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Solution

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So

A^{2}+B^{2}=C^{2}\\  C=\sqrt{A^{2}+B^{2}}\\ C=\sqrt{(487.68m)^{2}+(762m)^{2}}\\ C=904.7m

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