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snow_lady [41]
3 years ago
11

What distance does light travel in water, glass, and diamond during the time that it travels 1.0 m in vacuum? the refractive ind

ices for water, glass, and diamond are 1.33, 1.50, and 2.42, respectively.
Physics
2 answers:
alexdok [17]3 years ago
8 0
We are given with
distance traveled through vacuum = 1.0 m
refractive index of water = 1.33
refractive index of glass = 1.50
refractive index of diamond = 2.42

distance traveled through water is = 1.0/1.33 = 0.75 m
distance traveled through water is = 1.0/1.50 = 0.67 m
distance traveled through water is = 1.0/2.42 = 0.41 m
VARVARA [1.3K]3 years ago
4 0

Answer:

distance travelled in water = 1 / 1.33 = 0.75 m

distance travelled in glass = 1/ 1.5 = 0.66 m

distance travelled in diamond = 1/ 2.42 = 0.41 m

Explanation:

velocity of light in water, glass and diamond will be 1/1.33 , 1/1.5 and 1/2.42 times respectively of that in vacuum. So distance travelled in these mediums will be less.

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Determine the acceleration due to gravity?
MissTica
That's a weird graph, but judging from the units the acceleration is the slope of the graph.

a = (0.8 - 0.3)/(0.16 - 0.055) = 4.76 m/s²
8 0
3 years ago
What property of equality can be used to solve the equation. n – 14 = 25
Inga [223]

Do 25-14 and you will get your answer

7 0
2 years ago
Refer to a long, straight wire carrying constant current I. What can be concluded about the magnitude of the magnetic field at d
sergij07 [2.7K]

Answer:

<em>"the magnitude of the magnetic field at a point of distance a around a wire, carrying a constant current I, is inversely proportional to the distance a of the wire from that point"</em>

Explanation:

The magnitude of the magnetic field from a long straight wire (A approximately a finite length of wire at least for close points around the wire.) decreases with distance from the wire. It does not follow the inverse square rule as is the electric field from a point charge. We can then say that<em> "the magnitude of the magnetic field at a point of distance a around a wire, carrying a constant current I, is inversely proportional to the distance a of the wire from that point"</em>

From the Biot-Savart rule,

B = μI/2πR

where B is the magnitude of the magnetic field

I is the current through the wire

μ is the permeability of free space or vacuum

R is the distance between the point and the wire, in this case is = a

5 0
3 years ago
A particular coaxial cable is comprised of inner and outer conductors having radii 1 mm and 3 mm respectively, separated by air.
noname [10]

Answer:

The value is  \rho_s  =  4.026 *10^{-6} \  C/m^2

Explanation:

From the question we are told that

   The radius of the inner conductor  is  r_1 = 1 \ mm =  0.001 \ m

    The radius of the outer conductor is  r_2 = 3 \ mm = 0.003 \  m

    The potential at the outer conductor is  V = 1.5 kV  =  1.5 *10^{3} \  V

Generally the capacitance per length of the capacitor like set up of the two conductors is

      C= \frac{2 * \pi * \epsilon_o }{ ln [\frac{r_2}{r_1} ]}

Here \epsilon_o is the permitivity of free space with value  \epsilon_o =  8.85*10^{-12} C/(V \cdot m)

=>   C= \frac{2 *  3.142  * 8.85*10^{-12}  }{ ln [\frac{0.003}{0.001} ]}

=>   C= 50.6 *10^{-12} \  F/m

Generally given that the potential  of the outer conductor with respect to the inner conductor is positive it then mean that the outer conductor is positively charge

Generally the line  charge density of the outer  conductor is mathematically represented as

      \rho_l  =  C *  V

=>   \rho_d  =  50.6*10^{-12} *  1.5*10^{3}

=>   \rho_d  =  7.59*10^{-8} \  C/m

Generally the surface charge density is mathematically represented as

        \rho_s  =  \frac{\rho_l }{2 \pi * r_2 }    here 2 \pi r = (circumference \ of \ outer \  conductor  )

=>    \rho_s  =  \frac{7.59 *10^{-8} }{2* 3.142 * 0.003 }

=>    \rho_s  =  4.026 *10^{-6} \  C/m^2

3 0
3 years ago
What is E equal to in relativity? ​
vladimir1956 [14]

\huge \underline \mathtt \colorbox{cyan}{E=mc squared}

(E=mc^2)

<h3><u>Where</u><u>:</u></h3>

<u>m</u><u> </u><u>is mass</u>

<u>And c is a constant for speed of light</u>

7 0
2 years ago
Read 2 more answers
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