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guajiro [1.7K]
3 years ago
9

Can someone help me with this? Please-

Mathematics
1 answer:
lozanna [386]3 years ago
8 0

Answer:

C

Step-by-step explanation:

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Use the information provided to determine a 95% confidence interval for the population variance. A researcher was interested in
Leno4ka [110]

Answer:

The 95% confidence interval for the population variance is (8.80, 32.45).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the population variance is given as follows:

\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}

It is provided that:

<em>n</em> = 20

<em>s</em> = 3.9

Confidence level = 95%

⇒ <em>α</em> = 0.05

Compute the critical values of Chi-square:

\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.05/2, (20-1)}=\chi^{2}_{0.025,19}=32.852\\\\\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.05/2, (20-1)}=\chi^{2}_{0.975,19}=8.907

*Use a Chi-square table.

Compute the 95% confidence interval for the population variance as follows:

\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}

\frac{(20-1)\cdot (3.9)^{2}}{32.852}\leq \sigma^{2}\leq \frac{(20-1)\cdot (3.9)^{2}}{8.907}\\\\8.7967\leq \sigma^{2}\leq 32.4453\\\\8.80\leq \sigma^{2}\leq 32.45

Thus, the 95% confidence interval for the population variance is (8.80, 32.45).

4 0
3 years ago
What is the answer and work for these attached below
GrogVix [38]
-4(-5-b)=1/3(b+16) Multiply both sides by 3 to get rid of the fraction
-12(-5-b)=b+16  distribute the -12 to get rid of the parenthesis 
60+12b=b+16  get the b on the left side and non b values to the right side
11b=-44 solve for b
b=-44/11 simplify the fraction
b=-4

3/5(t+18)=-3(2-t)   multiply both sides by 5/3 to get rid of thefraction
t+18=-5(2-t)   distribute the -5 to get rid of the parenthises
t+18=-10+5t  get the t to the left side and non t values to the right
-4t=-28  solve for t
t=7
5 0
3 years ago
Is (ab^2) equivalent to ab^2? Explain.
Zarrin [17]

Answer: yes it is equivalent!

Step-by-step explanation:

all you do is take away the parentheses and then it is the same exact thing!

6 0
2 years ago
Read 2 more answers
Which number line represents the solution set for the inequality –4(x + 3) ≤ –2 – 2x?
Delicious77 [7]

Answer:

–4(x + 3) ≤ –2 – 2x

>>.....-4x -12 ≤ -2 -2x

>>  -12 +2 ≤ +2x  

>> - 10 ≤ 2x

>> -5 ≤ x............>> x >= -5  

Step-by-step explanation:

you didn't post any number lines...

3 0
3 years ago
I need help with this math question
ICE Princess25 [194]

Answer:

B. 5

Step-by-step explanation:

Step 1: Rewrite the equation a bit

\frac{7^\frac{3}{4}}{7^\frac{x}{8}}=\sqrt[8]{7}\\7^\frac{3}{4}^-^\frac{x}{8}=7^\frac{1}{8}

Step 2: Place a logarithm base 7 on both sides

7^\frac{3}{4}^-^\frac{x}{8}=7^\frac{1}{8}\\log_77^\frac{3}{4}^-^\frac{x}{8}=log_77^\frac{1}{8}\\(\frac{3}{4}-\frac{x}{8})log_77=\frac{1}{8}log_77\\(\frac{3}{4}-\frac{x}{8})1=\frac{1}{8}1\\\frac{3}{4}-\frac{x}{8}=\frac{1}{8}

Step 3: Solve for x

\frac{3}{4}-\frac{x}{8}=\frac{1}{8}\\\frac{6}{8}-\frac{x}{8}=\frac{1}{8}\\-\frac{x}{8}=-\frac{5}{8}\\\frac{x}{8}=\frac{5}{8}\\x=5

Neat exponent question :)

7 0
2 years ago
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