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DIA [1.3K]
3 years ago
14

The radius of a sphere was measured and found to be 20 cm with a possible error in measurement of at most 0.02 cm. What is the m

aximum error in using this value of the radius to compute the volume of the sphere
Mathematics
1 answer:
Elena L [17]3 years ago
7 0

Answer:

D(V)  = 100,48 cm³

Step-by-step explanation:

The volume of a sphere is:

V(s) = 4/3 π*r³

Where r is the radius of the sphere

If we take derivative of V  respect r

D(V)/ dr  =  4/3*3*π*r²    ⇒ D(V)/ dr  = 4*π*r²   ⇒ D(V) =  4*π*r²*dr

We know:

r = 20 cm     and   dr  =  0,02  ( at most)

Then

D(V)  = 4*π*(20)²*0.02  cm³

D(V)  = 32*π      

D(V)  = 100,48 cm³

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Answer:

1

Step-by-step explanation:

When dividing one fraction by another, the best way to solve it is to multiply by the reciprocal. The reciprocal just flipping the fraction over. So you would leave the 6/7 and the multiply by 14/12( because you are multiplying by the reciprocal). When you do that, you then can just multiply the top and the bottom to form one fraction. The numerator is 6*14 = 84, and the denominator is 7*14 = 84. So you are left with 84/84 which anything over itself is equal to one.

Hope this helps!

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Answer:

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Step-by-step explanation:

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