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tangare [24]
3 years ago
9

HELP PLZZZZ

Mathematics
1 answer:
JulijaS [17]3 years ago
8 0

Answer:

D(3,0) is correct answer

You might be interested in
How does the unit circle allow the trigonometric functions to be defined for all real numbers instead of just for acute angles?
Molodets [167]

Every point in the unit circle is identified either by its coordinates (x,y) or by the angle it forms with the x-axis, \alpha.

The trigonometric functions associate with every angle \alpha and the correspondant (x,y) coordinates the two values

\cos(\alpha)=x,\quad\sin(\alpha)=y

This procedure can be done for every angle \alpha, so you don't have to work with acute angles only.

8 0
3 years ago
The value -2 is a lower bound for the zeros of the function shown below.
Juliette [100K]

Answer:

  a) true

Step-by-step explanation:

The bottom-line numbers from synthetic division <em>alternate signs</em>, indicating that -2 is a lower bound. The given statement is true.

__

If the signs were all positive, it would indicate the proposed zero is an <em>upper bound</em>.

__

A graph shows all real zeros are greater than -2.

4 0
3 years ago
A bank is advertising the following savings account.
Vlad1618 [11]

Answer:

6.66%

Step-by-step explanation:

((1 + r/m)^n) - 1

Interest rate , r = 6.5%

m = number of compounding times per period = 4 (quarterly interest)

((1 + 0.065/4)^4) - 1

((1 + 0.01625) ^4) - 1

((1.01625)^4) - 1

1.06660 - 1

= 0.0666

0.0666 * 100%

= 6.66%

8 0
3 years ago
Solve the equation for x: c a−x/x−a =5x Answer: , a ≠ − 1/5
meriva

Answer:

\large\boxed{x=-\dfrac{1}{5}}

Step-by-step explanation:

\dfrac{a-x}{x-a}=5x\\\\\dfrac{(a-x)}{-(a-x)}=5x\qquad\text{cancel}\ (a-x)\\\\-1=5x\qquad\text{divide both sides by 5}\\\\-\dfrac{1}{5}=\dfrac{5x}{5}\to\boxed{x=-\dfrac{1}{5}}

7 0
3 years ago
Evaluate (-27)^-4/3 ((-27 to the power of -4/3))
masha68 [24]

Answer:

-1/81

Step-by-step explanation:

-27^-4/3

cbrt(-27^-4)

cbrt(-1/531441)

-1/81

5 0
3 years ago
Read 2 more answers
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