Which metal will produce H2 gas when added to a solution containing a strong acid?
1 answer:
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819 ml is the volume the gas will occupy at 30.0°C.
Explanation:
Data given:
initial volume of the gas V1 = 590 ml
initial temperature of the gas T1 = -55 degrees OR 218.15
final volume of the gas V2 = ?
final temperature of the gas T2 = 30 degrees OR 303.15
Charles' Law equation is used to calculate the volume of gas at 30 degrees from the data given in the question.
=
V2 =
V2 =
V2 = 819 ml
The final volume of the gas would be 819 ml.
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Step by Step Explanation
From the question,
the dimensions of the tank are;
L = 30 cm, way =0.075m and H = 15 cm
The density of water is given as
The unit of density given in the question means that the mass of the water is in grams and the volume should also be in
To find the volume of the water, we first convert the units of dimensions given in inches and metres to centimetres
This implies that ,
Also,
This implies that,
Now, the volume of water in the tank can hold, can be found from the relation;
This implies that,
Finally, we can calculate the mass of the water from the relation given;
This in implies that
Hence the fish tank can hold 0.857g water.
From the question,
the dimensions of the tank are;
L = 30 cm, way =0.075m and H = 15 cm
The density of water is given as
The unit of density given in the question means that the mass of the water is in grams and the volume should also be in
To find the volume of the water, we first convert the units of dimensions given in inches and metres to centimetres
This implies that ,
Also,
This implies that,
Now, the volume of water in the tank can hold, can be found from the relation;
This implies that,
Finally, we can calculate the mass of the water from the relation given;
This in implies that
Hence the fish tank can hold 0.857g water.