Question

Given the following information:

Answer 1

Answer:

8572.5 grams of the water will fish tank can hold.

Explanation:

Volume of the fish tank = V

Length of fish tank = l = 30 cm

Width of fish tank = w  = 0.075 m = 7.5 cm

1 m = 100 cm

Length of fish tank = h = 15 inches = 38.1 cm

1 inch = 2.54 cm

$V=l\times w\times h=30 cm\times 0.075 cm\times 38.1 cm=85.725 cm^3$

Volume of fish tank = Volume of water = v = $8572.5 cm^3$

Mass of water in the tank = m

Density of the water $d= 1 g/cm^3$

$D=\frac{m}{v}$

$m=d\times v=1 g/cm^3\times 8572.5 cm^3=8572.5 g$

8572.5 grams of the water will fish tank can hold.

Answer 2

Step by Step Explanation

From the question,
the dimensions of the tank are;

L = 30 cm, way =0.075m and H = 15 cm

The density of water is given as
$D = 1g {cm}^{ - 3}$

The unit of density given in the question means that the mass of the water is in grams and the volume should also be in
${cm}^{3}$

To find the volume of the water, we first convert the units of dimensions given in inches and metres to centimetres

$1 inch = 2.54 cm$

This implies that ,

$H=15 inches=15×2.54cm=38.1cm$

Also,

$100cm=1m$

This implies that,
$w= \frac{0.075}{100 } = 7.5 \times {10}^{ - 4} cm$

Now, the volume of water in the tank can hold, can be found from the relation;

$V=L\times W\times H$

This implies that,

$v = 30cm \times (7.5 \times {10}^{ - 4} )cm \times 38.1cm$

$v = 0.857 {cm}^{3} \: to \: 3 \: d.p$

Finally, we can calculate the mass of the water from the relation given;

$D=\frac{M}{V}$

This in implies that

$1g {cm}^{ - 3} = \frac{m}{0.857 {cm}^{3} }$
$m = 1g {cm}^{ - 3} \times 0.857 {cm}^{3}$
$m = 0.857g$


Hence the fish tank can hold 0.857g water.