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Montano1993 [528]
3 years ago
11

In the periodic table below, shade all the elements for which the neutral atom has a valence electron configuration of ns2np3 ,

where n stands for an integer.
Chemistry
1 answer:
Lorico [155]3 years ago
5 0
Answer is: chemical elements<span> in </span>group 15<span> of the </span>periodic table have <span>neutral atom with a valence electron configuration of ns</span>²<span>np</span>³<span>.
</span>Nitrogen: [He] 2s² 2p³.
Phosphorus: [Ne] 3s² 3p³.
Arsenic: <span>[Ar] 3d</span>¹⁰ 4s² 4p³.
Bismuth: <span>[Xe] 4f</span>¹⁴ 5d¹⁰ 6s² 6p³.
Moscovium: predicted [Rn] 5f¹⁴<span> 6d</span>¹⁰<span> 7s</span>² 7p³.
These elements have 5 valence electrons.

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How does the number of subatomic particles change as the carbon isotope<br> decays?
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Answer:

Explanation:

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2 years ago
How do synthesis reactions and a decomposition reactions differ
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8 0
3 years ago
At 9°C a gas has a volume of 6.17 L. What is its volume when the gas is at standard temperature?
Alex17521 [72]

Answer:

V₂ = 5.97 L

Explanation:

Given data:

Initial temperature = 9°C (9+273 = 282 K)

Initial volume of gas  = 6.17 L

Final volume of gas = ?

Final temperature = standard = 273 K

Solution:

Formula:

The Charles Law will be apply to solve the given problem.

According to this law, 'the volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure'

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 6.17 L ×  273K /  282  k

V₂ = 1684.41 L.K / 282 K

V₂ = 5.97 L

5 0
3 years ago
(b)
Luda [366]

The maximum mass of anhydrous zinc chloride that could be obtained from the products of the reaction is 8.18 g

<h3>Stoichiometry </h3>

From the question, we are to determine the maximum mass of anhydrous zinc chloride that could be obtained

From the given balanced chemical equation,

ZnO + 2HCl → ZnCl₂ + H₂O

This means 1 mole of ZnO will completely react with 2 moles of HCl to produce 1 mole of ZnCl₂ and 1 mole of H₂O

From the given information

Number of moles of ZnO = 0.0830 mole

Now, we will calculate the number of moles of HCl that is present

Volume of HCl added = 100 cm³ = 0.1 dm³

Concentration of the HCl = 1.20 mol/dm³

Using the formula,

Number of moles = Concentration × Volume

Number of moles of HCl present = 1.20 × 0.1 = 0.120 mole

Since

1 mole of ZnO will completely react with 2 moles of HCl to produce 1 mole of ZnCl₂

Then,

0.06 mole of ZnO will react with the 0.120 mole of HCl to produce 0.06 mole of ZnCl₂

Therefore, maximum number of moles of anhydrous zinc chloride that could be produced is 0.06 mole

Now, for the maximum mass that could be produced

Using the formula,

Mass = Number of moles × Molar mass

Molar mass of ZnCl₂ = 136.286 g/mol

Then,

Mass = 0.06 × 136.286

Mass = 8.17716 g

Mass ≅ 8.18 g

Hence, the maximum mass of anhydrous zinc chloride that could be obtained from the products of the reaction is 8.18 g

Learn more on Stoichiometry here: brainly.com/question/11910892

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