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3 years ago

This problem has been solved!

Chemistry

1 answer:

Vanyuwa [196]3 years ago

5 0

Answer:

NaCl and water: Ion - Dipolo forces

NaCl and Hexane: Ion-ion force between Na+ and Cl− ions and London dispersion force between two hexane molecules

Explanation:

NaCl and water:

The ion-dipole force is established between an ion and a polar molecule. Polar molecules are dipoles, they have a positive end and a negative end.

H2O has an important charge separation in its atoms (the H has a positive partial charge and the O has a negative partial charge) and this causes permanent electrical dipoles in the water molecules.

Sodium chloride is an ionic compound formed of positive and negative charge ions, Na + and Cl-. Depending on their charge, these ions will be attracted to opposite charges in the water molecules (H attracts chloride ions and O attracts sodium ions), causing the salt to dissolve in water.

NaCl and Hexane:

The dispersion forces of London occur between apolar molecules, and they occur because when two molecules approach a distortion of the electronic clouds of both originates, generating in them, transient induced dipoles, due to the movement of the electrons, so it allows interact with each other.

Hexane is a non-polar molecule, which are those that have no charge separation within the molecules. Then there is London dispersion force between two hexane molecules. 

On the other hand, the ion-ion force is produced between ions of the same or different charge, where ions with charges of opposite sign attract each other and ions with charges of the same sign repel each other. This is the force that occurs between the NaCl ions.

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Main ingredients of plastic bags and natural resources used please

DanielleElmas [232]

polyethylene or polythene are the main ingredients

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3 years ago

A solution is prepared by adding 0.0231moles of H3O+ ions to 3.33L of water. What is the pH of this solution

MrMuchimi

Answer:

2.15

Explanation:

For this question, we have to remember the pH formula:

$pH~=~-Log[H_3O^+]$

By definition, the pH value is calculated when we do the -Log of the concentration of the hydronium ions ( $H_3O^+$ ). So, the next step is the calculation of the concentration of the hydronium ions. For this, we have to use the molarity formula:

$M=\frac{mol}{L}$

We already know the number of moles (0.0231 moles) and the volume (3.33 L). So, we can plug the values into the molarity formula:

$M=\frac{0.0231~moles}{3.33~L}=0.00693~M$

With this value, now we can calculate the pH value:

$pH~=~-Log[0.00693~M]~=~2.15$

The pH would be 2.15

I hope it helps!

8 0

2 years ago

A plant extract can be obtained with organic solvents such as acetone or ethyl alcohol, and is composed of plant pigments such a

prohojiy [21]

Answer:

Here's what I get

Explanation:

A plant extract is a mixture because it contains different substances: acetone or ethanol, chlorophylls A and B, carotene and xanthophylls.

It is homogeneous because it is a solution. There is only one phase: the liquid phase. You cannot see the pigments as separate phases.

You can separate the pigments by paper, thin layer, or column chromatography.

Many schools use paper chromatography, because paper is cheap.

As the mixture of pigments follows the solvent up the paper, they separate into different coloured bands according to their attractive forces to the cellulose in the paper.

The chlorophylls are strongly attracted to the paper, so they don't travel very far.

The nonpolar carotene molecules have little attraction to the polar cellulose, so they are carried along by the solvent front.

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3 years ago

In this experiment, we will be performing a titration with a buret. place the steps in order. 1. record the ph when 0.0 ml of na

77julia77 [94]

I am guessing that your solutions of HCl and of NaOH have approximately the same concentrations. Then the equivalence point will occur at pH 7 near 25 mL NaOH.

The steps are already in the correct order.

1. Record the pH when you have added 0 mL of NaOH to your beaker containing 25 mL of HCl and 25 mL of deionized water.

2. Record the pH of your partially neutralized HCl solution when you have added 5.00 mL of NaOH from the buret.

3. Record the pH of your partially neutralized HCl solution when you have added 10.00 mL, 15.00 mL and 20.00 mL of NaOH.

4. Record the NaOH of your partially neutralized HCl solution when you have added 21.00 mL, 22.00 mL, 23.00 mL and 24.00 mL of NaOH.

5. Add NaOH one drop at a time until you reach a pH of 7.00, then record the volume of NaOH added from the buret ( at about 25 mL).

6. Record the pH of your basic HCl-NaOH solution when you have added 26.00 mL, 27.00 mL, 28.00 mL, 29.00 mL and 30.00 mL of NaOH.

7. Record the pH of your basic HCl-NaOH solution when you have added 35.00 mL, 40.00 mL, 45.00 mL and 50.00 mL of NaOH from your 50mL buret.

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3 years ago

Based on the molar masses. how can you tell that an equation is balanced

harkovskaia [24]

You can tell if each side of the equation has the same molar mass.

3 0

2 years ago