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Svetach [21]
3 years ago
11

A chlorine atom in its ground state has a total of seven electrons in orbitals related to the atoms third energy level. how many

of the seven electrons occupy the p orbital
Chemistry
1 answer:
kiruha [24]3 years ago
7 0
<span>5 electrons

</span>The electron configuration of an atom shows or describes the distribution of electrons in their atomic orbitals. In particular, it shows the distribution in terms of the principal energy levels or electron shells (reflected by the numbers 1, 2, 3, 4, 5, 6, 7) and their corresponding subshells (reflected by the letters s,p,d,f,g) composed of atomic orbitals. 

The maximum number of electrons in the s-subshell is 2, in the p-subshell, 6, in the d-subshell, 10, in the f-subshell, 14, and in the g-subshell, 18. In the electron configuration of an atom, the number of electrons in the subshell for a given atom is reflected by a number (in superscript) next to the corresponding letter of the subshell. 
 
<span>The electron configuration of a chlorine atom in its ground state is 
</span>1s^{2}2s^{2}2p^{6}3s^{2}3p^{5}

Thus, the number of electrons in the 3rd energy level in the p-subshell is 5 (3p^{5} as seen in the electron configuration of the atom). 
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Correct Question: what is the oxidizing agent in the reaction.

2MnO4–(aq) +10Cl–(aq) + 16H+(aq) --------> 5Cl2(g) + 2Mn2+(aq) +8H2O(l)

Answer: MnO4-is the oxidizing agent

Explanation:

In the reaction 2MnO4–(aq) +10Cl–(aq) + 16H+(aq) --------> 5Cl2(g) + 2Mn2+(aq) +8H2O(l)

Oxidizing agent oxidizes other molecules while the themselves get reduced.

oxidizing agents give away Oxygen to other compounds.

MnO4-is the oxidizing agent because

On the reactants side

Oxidation number of Mn in 2MnO4- is +7

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On the products side

Oxidation number of Mn is +2

While oxidation number of Cl is zero

Therefore the oxidizing agent is 2MnO4 because is oxidizes Chlorine from -1 to 0 while itself got reduced from oxidation state of +7 to +2

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