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Svetach [21]
2 years ago
11

A chlorine atom in its ground state has a total of seven electrons in orbitals related to the atoms third energy level. how many

of the seven electrons occupy the p orbital
Chemistry
1 answer:
kiruha [24]2 years ago
7 0
<span>5 electrons

</span>The electron configuration of an atom shows or describes the distribution of electrons in their atomic orbitals. In particular, it shows the distribution in terms of the principal energy levels or electron shells (reflected by the numbers 1, 2, 3, 4, 5, 6, 7) and their corresponding subshells (reflected by the letters s,p,d,f,g) composed of atomic orbitals. 

The maximum number of electrons in the s-subshell is 2, in the p-subshell, 6, in the d-subshell, 10, in the f-subshell, 14, and in the g-subshell, 18. In the electron configuration of an atom, the number of electrons in the subshell for a given atom is reflected by a number (in superscript) next to the corresponding letter of the subshell. 
 
<span>The electron configuration of a chlorine atom in its ground state is 
</span>1s^{2}2s^{2}2p^{6}3s^{2}3p^{5}

Thus, the number of electrons in the 3rd energy level in the p-subshell is 5 (3p^{5} as seen in the electron configuration of the atom). 
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Explanation:

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5 0
2 years ago
What is molarity of 47.0 g KCl dissolved in enough water to give 375 mL of solution?
natita [175]

This question provides us –

  • Weight of \bf  KCl is = 47 g
  • Volume, V = 375 mL

__________________________________________

  • Molar Mass of \bf   KCl –

\qquad \twoheadrightarrow\bf  39.0983 \times 35.453

\qquad \twoheadrightarrow\bf 74.5513

<u>Using formula</u> –

\qquad \purple{\twoheadrightarrow\bf Molarity _{(Solution)} =  \dfrac{ W\times 1000}{MV}}

\qquad \twoheadrightarrow\bf Molarity _{(Solution)}  = \dfrac{ 47 \times 1000}{74.5513\times 375}

\qquad \twoheadrightarrow\bf Molarity _{(Solution)}  = \dfrac{47000}{27956.7375}

\qquad \twoheadrightarrow\bf Molarity _{(Solution)}  = \cancel{\dfrac{47000}{27956.7375}}

\qquad \twoheadrightarrow\bf Molarity _{(Solution)}  = 1.68117M

\qquad \pink{\twoheadrightarrow\bf Molarity _{(Solution)}  = 1.7M}

  • Henceforth, Molarity of the solution is = 1.7M

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6 0
2 years ago
1. A part of a neuron is a(n) A. nerve B. cell body C. receptor D. acetylcholine
katovenus [111]
A neuron has 4 basic part the dendrites the cell body
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3 years ago
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8 0
3 years ago
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Natasha2012 [34]
For this problem, we use the formula for sensible heat which is written below:

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Q = (55.5 g)(<span>0.214 cal/g</span>·°C)(48.6°C- 23°C)
<em>Q = 304.05 cal</em>
4 0
3 years ago
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