Answer:
8.25 moles
Explanation:
Given parameters:
Number of moles of Al produced = 11 moles
Unknown:
Number of moles of oxygen produced = ?
Solution:
To solve this problem, we need to understand the problem.
The decomposition of an aluminium oxide must has produced oxygen and aluminium,
2Al₂O₃ → 4Al + 3O₂
now since the known is the oxygen gas; we can find the unknown aluminium:
3 mole of O₂ was produced with 4 mole of Al
x mole of O₂ will be produced with 11 moles of Al
x = 
= 8.25 moles
Answer:
C
Explanation:
when the equation is balanced, 2 moles of sodium is to 1 mole of hydrogen in the mole ratio so we need to find how many moles of sodium will produce hydrogen then we cross multiply
It explodes all over the place
The mass of sodium chloride : 3.5 g
<h3>Further explanation</h3>
Given
Reaction :
2.5g of sodium sulphate + 4.5g of barium chloride ⇒ 3.5g of barium sulphate + sodium chloride
Required
The mass of sodium chloride
Solution
Conservation of mass applies to a closed system, <em>where the masses before and after the reaction are the same</em>
From the reaction :
mass of reactants = 2.5 g + 4.5 g = 7.0 g
mass of products = 3.5 g + mass of sodium chloride
mass of reactants = mass of products
7.0 g = 3.5 g + mass of sodium chloride
mass of sodium chloride = 7 g - 3.5 g =3.5 g
