The answer is A …a …a … I think
Formula for Barium Nitrate = Ba(NO3)2
Thus based on stoichiometry:
1 mole of Ba(NO3)2 contains 2 moles of NO3-
Therefore, concentration of nitrate ion NO3- would be = 2*0.240 = 0.480 M
Use the relation:
V1M1 = V2M2
V1 = V2M2/M1 = 0.500 L * 0.0800/0.480 = 0.0833 L
Thus, 0.0833 L or 83.3 ml solution of Ba(NO3)2 would be required.
Answer: The freezing point of a 0.765 m solution of nitrobenzene in naphthalene is 
Explanation:
Depression in freezing point is given by:
= Depression in freezing point
i= vant hoff factor = 1 (for non electrolyte such as nitrobenzene)
= freezing point constant = 
m= molality = 0.765
Thus the freezing point of a 0.765 m solution of nitrobenzene in naphthalene is
Answer:
I think it is number 4 which is 3.87 v
Answer:
1.Products
2.Reactants
3.Activation
4.Chemical potential energy
5.Energy
6.Activated
7.Complex
8.Progress of reaction
9.Enthalpy of Reaction
