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2 years ago

6

Perform the following calculations and express the answer with the proper significant

2 answers:

Romashka [77]2 years ago

8 0

Answer:

The answer is

210.6+14.57=225.17mm.

Anuta_ua [19.1K]2 years ago

8 0

Answer:

Explanation:

0.15 MG +1.15 MG +2.051 MG

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An unknown piece of metal weighing 95.0 g is heated to 98.0°C. It is dropped into 250.0 g of water at 23.0°C. When equilibrium i

lutik1710 [3]

Answer:

$C_{metal}=126.6\frac{J}{g\°C}$

Explanation:

Hello!

In this case, when two substances at different temperature are put in contact and an equilibrium temperature is attained, we can evidence that the heat lost by the hot substance (metal) is gained by the cold substance (water) and we can write:

$Q_{metal}=-Q_{water}$

Which can be also written as:

$m_{metal}C_{metal}(T_{EQ}-T_{metal})=-m_{water}C_{water}(T_{EQ}-T_{water})$

Thus, since we need the specific heat of the metal, we solve for it as shown below:

$C_{metal}=\frac{m_{water}C_{water}(T_{EQ}-T_{water})}{-m_{metal}(T_{EQ}-T_{metal})} \\\\C_{metal}=\frac{250.0g*4.184\frac{J}{g\°C}(29.0\°C-98.0\°C)}{95.0g(29.0\°C-23.0\°C)} \\\\C_{metal}=126.6\frac{J}{g\°C}$

Best regards.

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2 years ago

When our body temperature starts to increase, the blood flow to the skin increases and we produce large volumes of sweat, which

Troyanec [42]

I took the U.S.A
test prep and the answer is B

5 0

3 years ago

Read 2 more answers

How many grams of zinc sulfide are used to produce 1.28 grams of zinc oxide?

Lostsunrise [7]

Answer:

0.012288122055459

Explanation:

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6 0

2 years ago

Nitroglycerine decomposes violently according to the chemical equation below. What mass of carbon dioxide gas is produced from t

AveGali [126]

Answer : The mass of $CO_2$ produced is, 7.74 grams

Solution : Given,

Mass of $C_3H_5(NO_3)_3$ = 13.3 g

Molar mass of $C_3H_5(NO_3)_3$ = 227 g/mole

Molar mass of $CO_2$ = 44 g/mole

First we have to calculate the moles of $C_3H_5(NO_3)_3$ .

$\text{ Moles of }C_3H_5(NO_3)_3=\frac{\text{ Mass of }C_3H_5(NO_3)_3}{\text{ Molar mass of }C_3H_5(NO_3)_3}=\frac{13.3g}{227g/mole}=0.0586moles$

Now we have to calculate the moles of $CO_2$

The balanced chemical reaction is,

$4C_3H_5(NO_3)_3\rightarrow 12CO_2(g)+6N_2(g)+10H_2O(g)+O_2(g)$

From the reaction, we conclude that

As, 4 mole of $C_3H_5(NO_3)_3$ react to give 12 mole of $CO_2$

So, 0.0586 moles of $C_3H_5(NO_3)_3$ react to give $0.0586\times \frac{12}{4}=0.176$ moles of $CO_2$

Now we have to calculate the mass of $CO_2$

$\text{ Mass of }CO_2=\text{ Moles of }CO_2\times \text{ Molar mass of }CO_2$

$\text{ Mass of }CO_2=(0.176moles)\times (44g/mole)=7.74g$

Thus, the mass of $CO_2$ produced is, 7.74 grams

4 0

3 years ago

Chemistry. Question is on photo. Will mark Brainy for whoever gets this right.

ozzi

Answer:

49.18 eV hope this helps

6 0

2 years ago