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ryzh [129]
4 years ago
6

Sebanyak 4,5 mg magnesium hidroksida (Mg(OH)2) dapat larut dalam 500 ml air. nyatakan kelarutan Mg(OH)2 dalam mol L-1

Chemistry
1 answer:
Schach [20]4 years ago
8 0
S =gr/mr x 1000/v s=4,5/58 x 1000/500 s=4,5/58 x 2 s=9/58 s= 0,1
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A 20.00 ml sample of a solution of sr(oh)2 is titrated to the equivalence point with 40.03 ml of 0.1159 n hcl. what is the molar
goblinko [34]
The   molarity  of Sr(OH)2  solution is  =  0.1159 M

    calculation
write the equation  for reaction
that is,  Sr(OH)2 +2HCl→ SrCl2 + 2 H2O

then finds the mole  of HCl used

moles = molarity x volume 
=40.03 x0.1159 =  4.639 moles

by  use of mole ratio between Sr(OH)2 to  HCL which is 1 :2  the moles of Sr(OH)2  is therefore =  4.639  x1/2 = 2.312  moles

molarity  of  Sr(OH)2  is =  moles  / volume

=2.312 /20 =0.1159 M
3 0
4 years ago
What type of energy has caused the fewest deaths per unit of energy produced?
mash [69]

Answer: Nuclear energy is by far the safest energy source in this comparison – it results in more than 442 times fewer deaths than the 'dirtiest' forms of coal; 330 times fewer than coal; 250 times less than oil; and 38 times fewer than gas.

4 0
3 years ago
Oxygen and hydrogen are most likely to form what type of bond?
tekilochka [14]
Oxygen and Hydrogen would most likely form a covalent bond that is polar, or a polar covalent bond. Due to the electronegativity difference between the 2 elements, unequal sharing of the valence electrons will occur, electrons being in closer proximity to Oxygen and farther away from Hydrogen. Resulting in the characteristic partial positive and negative charges to appear for the respective elements.
3 0
3 years ago
Read 2 more answers
22. A piece of wood board contains approximately 6.76 X 1023 molecules of wood, C2H4920, how
Licemer1 [7]

Answer:

<h2>1.23 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{6.76 \times  {10}^{23} }{6.02 \times  {10}^{23} }  =  \frac{6.76}{6.02}  \\  = 1.22923...

We have the final answer as

<h3>1.23 moles</h3>

Hope this helps you

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3 years ago
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Julli [10]

Answer:

Full answer in explanation

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