Question

What is the mass, in grams, of 28.80 ml of acetone?

Answer 1

density of acetone in gm/cm^3 is 0.791

=28.80cm^3*0.791 g/cm63

=22.78 g

Answer 2

The given question is incomplete. The complete question is as follows.

What is the mass, in grams, of 28.80 ml of acetone? Acetone (nail polish remover) has a density of 0.7857 $g/cm^{3}$.

Explanation:

It is known that density is the mass of a substance occupied in per unit volume of the object.

Mathematically,    Density = $\frac{mass}{volume}$

Therefore, putting the given values into the above formula as follows.

               Density = $\frac{mass}{volume}$

   0.7857 $g/cm^{3}$ = $\frac{mass}{28.80 m^{3}}$   (1 ml = 1 $m^{3}$)

                 mass = 22.62 g

Thus, we can conclude that mass of given acetone is 22.62 g.