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4 years ago

What is the mass, in grams, of 28.80 ml of acetone?

Chemistry

2 answers:

oee [108]4 years ago

8 0

density of acetone in gm/cm^3 is 0.791

=28.80cm^3*0.791 g/cm63

=22.78 g

yKpoI14uk [10]4 years ago

7 0

The given question is incomplete. The complete question is as follows.

What is the mass, in grams, of 28.80 ml of acetone? Acetone (nail polish remover) has a density of 0.7857 $g/cm^{3}$ .

Explanation:

It is known that density is the mass of a substance occupied in per unit volume of the object.

Mathematically, Density = $\frac{mass}{volume}$

Therefore, putting the given values into the above formula as follows.

Density = $\frac{mass}{volume}$

0.7857 $g/cm^{3}$ = $\frac{mass}{28.80 m^{3}}$ (1 ml = 1 $m^{3}$ )

mass = 22.62 g

Thus, we can conclude that mass of given acetone is 22.62 g.

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denis23 [38]

Answer: The molecular formula of aspirin is $C_8H_8O_2$

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

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Mass of H = 4.5 g

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Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{60.0g}{12g/mole}=5.00moles$

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Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{5.00}{2.22}=2$

For H = $\frac{4.5}{2.22}=2$

For O = $\frac{2.22}{2.22}=1$

The ratio of C : H: O= 2: 2: 1

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The molecular weight = 180.2 g/mole

Now we have to calculate the molecular formula.

$n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{180.2}{42}=4$

The molecular formula will be= $4\times C_2H_2O=C_8H_8O_2$

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