Answer:
The number of business students that must be randomly selected to estimate the mean monthly earnings of business students at one college is 64.
Step-by-step explanation:
The (1 - <em>α</em>) % confidence interval for population mean is:

The margin of error for this interval is:

The information provided is:
<em>σ</em> = $569
MOE = $140
Confidence level = 95%
<em>α</em> = 5%
Compute the critical value of <em>z</em> for <em>α</em> = 5% as follows:

*Use a <em>z</em>-table.
Compute the sample size required as follows:
![n=[\frac{z_{\alpha/2}\times \sigma}{MOE}]^{2}](https://tex.z-dn.net/?f=n%3D%5B%5Cfrac%7Bz_%7B%5Calpha%2F2%7D%5Ctimes%20%5Csigma%7D%7BMOE%7D%5D%5E%7B2%7D)
![=[\frac{1.96\times 569}{140}]^{2}\\\\=63.457156\\\\\approx 64](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B1.96%5Ctimes%20569%7D%7B140%7D%5D%5E%7B2%7D%5C%5C%5C%5C%3D63.457156%5C%5C%5C%5C%5Capprox%2064)
Thus, the number of business students that must be randomly selected to estimate the mean monthly earnings of business students at one college is 64.
Angle ACF complementary, because it's angle equals up to 90.and FCB is complementary also, because the angle equals 90. hope i helped.
Answer:
y=7.5
Step-by-step explanation:
25y -15y =75
10y=75
y=7.5
plz mark brainliest
Answer:
A. 0
Step-by-step explanation:
If the slopes are the same but the y-intercepts are different, I can assume that the functions are parallel to each other. For this reason, they will never intercept.
Answer:
1/6,3/12,1/3
Step-by-step explanation:
3/12=3/12
1/6=2/12
1/3=4/12