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3 years ago

Three objects A, B, C are placed 50.0 cm apart

Physics

2 answers:

NemiM [27]3 years ago

5 0

Answer:

F= 1.334x10^-8N

Explanation:.

F(AB)=100G/(50x10^-2)^2

F(CB)=150G/(50x10^-2)^2

F(net)=F(AB)-F(CB)

Note that, distance should be in meters so convert it into meter or directly use its meter value (50x10^-2m)

Substitude the value of G=6.67x10^-11Nm^2/kg^2 into the equations and the do the calculations you will obtain the answer.

vlada-n [284]3 years ago

3 0

Answer: 1.33 ×10^-8 N

Explanation:

In the picture.

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