Calculate the work required to lift a 2000 kg vehicle on a lift, 2.0 m at constant speed, assuming friction averages 500 N..a. 3
1 answer:
Answer:
c. 40200 J
Explanation:
Assume gravitational constant g = 9.8m/s2. The weight of the 2000kg vehicle is
In addition to the friction averaging at 500N, the total force is
F = 20000 + 500 = 20100 N
The work required to generate this force over a distance of 2m would be
F*s = 20500 * 2 = 40200 J
So c.40200 J is the correct answer
You might be interested in
Answer:
The formula for Impedance for circuit with R, C, and L are:
The impedance Z of the series RLC circuit depend upon angular frequency ω. Impedance is measured in ohms and resistance (R), inductance reactance and capacitive reactance. Series RLC circuit consist of the resistance, a capacitance and an inductance connected in the circuits. Electrical impedance is the measurement of the opposition that a circuit present in a current.
Answer:
r= 3.2 cm
Explanation:
Given that
I= 8.7 A
B= 5.4 x 10⁻⁵ T
μo=1.25664 x 10⁻⁶
We know that magnetic filed in wire at a distance r given as
By putting the values
r=0.032 m
r= 3.2 cm