Calculate the work required to lift a 2000 kg vehicle on a lift, 2.0 m at constant speed, assuming friction averages 500 N..a. 3
1 answer:
Answer:
c. 40200 J
Explanation:
Assume gravitational constant g = 9.8m/s2. The weight of the 2000kg vehicle is
In addition to the friction averaging at 500N, the total force is
F = 20000 + 500 = 20100 N
The work required to generate this force over a distance of 2m would be
F*s = 20500 * 2 = 40200 J
So c.40200 J is the correct answer
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Answer:
The voltage drop across the bulb is 115 V
Explanation:
The voltage drop equation is given by:
Where:
ΔW is the total work done (4.6kJ)
Δq is the total charge
We need to use the definition of electric current to find Δq
Where:
I is the current (2 A)
Δt is the time (20 s)
Then, we can put this value of charge in the voltage equation.
Therefore, the voltage drop across the bulb is 115 V.
I hope it helps you!