Answer:
3.13 m/s
Explanation:
From the question,
Since the flea spring started from rest,
Ek = W................... Equation 1
Where Ek = Kinetic Energy of the flea spring, W = work done on the flea spring.
But,
Ek = 1/2mv²............ Equation 2
Where m = mass of the flea spring, v = flea's speed when it leaves the ground.
substitute equation 2 into equation 1
1/2mv² = W.................... Equation 3
make v the subject of the equation
v = √(2W/m)................. Equation 4
Given: W = 3.6×10⁻⁴ J, m = 2.3×10⁻⁴ kg
Substitute into equation 4
v = √[2×3.6×10⁻⁴ )/2.3×10⁻⁴]
v = 7.2/2.3
v = 3.13 m/s
Hence the flea's speed when it leaves the ground = 3.13 m/s
Answer:
Explanation:
mass of probe m = 474 Kg
initial speed u = 275 m /s
force acting on it F = 5.6 x 10⁻² N
displacement s = 2.42 x 10⁹ m
A )
initial kinetic energy = 1/2 m u² , m is mass of probe.
= .5 x 474 x 275²
= 17923125 J
B )
work done by engine
= force x displacement
= 5.6 x 10⁻² x 2.42 x 10⁹
= 13.55 x 10⁷ J
C ) Final kinetic energy
= Initial K E + work done by force on it
= 17923125 +13.55 x 10⁷
= 1.79 x 10⁷ + 13.55 x 10⁷
= 15.34 x 10⁷ J
D ) If v be its velocity
1/2 m v² = 15.34 x 10⁷
1/2 x 474 x v² = 15.34 x 10⁷
v² = 64.72 x 10⁴
v = 8.04 x 10² m /s
= 804 m /s
The vanishing of an ionic solid (like table salt) would be an example of acting like a solvent
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