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katrin2010 [14]
3 years ago
15

How do you identify the solute and solvent of SO^2

Chemistry
2 answers:
scoray [572]3 years ago
3 0

Answer:

How to identify a solute and solvent?

It is not possible to identify the solute and solvent as different substances in a solution. In a solution of table salt and water, the salt is the solute and the water is the solvent. In the cells of your body, substances such as calcium ions and sugar are solutes, and water is the solvent.

Explanation:

masha68 [24]3 years ago
3 0

Answer:

Fórmula química: SO2 estado=Gas

Punto de ebullición: -10 °C (14 °F)

Masa molar media: 64,06 g/mol

Punto de fusión: -72 °C (-97,60 °F)

Denominación según IUPAC: Dióxido de azufre

Explanation:

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how many electrons are transferred between the cation and anion to form the ionic bond in one formula unit of each compound? (1
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Answer:

The answer to your question is:

Explanation:

Compound                 Cation                 Anion         Number of electrons

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8 0
3 years ago
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You turn on your gas fireplace at home and wonder why you don't immediately feel the
DENIUS [597]

Answer:

the (air) atmosphere

Explanation:

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10 m3 of carbon dioxide is originally at a temperature of 50 °C and pressure of 10 kPa. Determine the new density and volume of
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Answer : The new density and new volume of carbon dioxide gas is 0.2281 g/L and 7.2m^3 respectively.

Explanation :

First we have to calculate the new or final volume of carbon dioxide gas.

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 10 kPa

P_2 = final pressure of gas = 15 kPa

V_1 = initial volume of gas = 10m^3

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 50^oC=273+50=323K

T_2 = final temperature of gas = 75^oC=273+75=348K

Now put all the given values in the above equation, we get:

\frac{10kPa\times 10m^3}{323K}=\frac{15kPa\times V_2}{348K}

V_2=7.2m^3

The new volume of carbon dioxide gas is 7.2m^3

Now we have to calculate the new density of carbon dioxide gas.

PV=nRT\\\\PV=\frac{m}{M}RT\\\\P=\frac{m}{V}\frac{RT}{M}\\\\P=\rho \frac{RT}{M}\\\\\rho=\frac{PM}{RT}

Formula for new density will be:

\rho_2=\frac{P_2M}{RT_2}

where,

P_2 = new pressure of gas = 15 kPa

T_2 = new temperature of gas = 75^oC=273+75=348K

M = molar mass of carbon dioxide gas = 44 g/mole

R = gas constant = 8.314 L.kPa/mol.K

\rho = new density

Now put all the given values in the above equation, we get:

\rho_2=\frac{(15kPa)\times (44g/mole)}{(8.314L.kPa/mol.K)\times (348K)}

\rho_2=0.2281g/L

The new density of carbon dioxide gas is 0.2281 g/L

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Answer:

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