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dybincka [34]
3 years ago
14

If we read the reaction as X + Y → Z + Q it is A. endothermic B. exothermic

Chemistry
2 answers:
Korvikt [17]3 years ago
4 0
As you can see in the picture we have +ΔH so that means for this reaction we need to GET heat. so the answer is A. endothermic :))
i hope this is helpful
have a nice day 
kupik [55]3 years ago
3 0

Answer: The given reaction is a type of endothermic reaction.

Explanation:

There are 2 types of reaction classified on the basis of heat released or absorbed:

1. Exothermic reactions: In these reactions, the heat is released because the energy of products is less than the energy of the reactants. \Delta H for these reactions is negative.

2. Endothermic reactions: In these reactions, heat is absorbed by the reactants because the energy of the products is more than the energy of the reactants. \Delta H for these reactions if positive.

In the given question, the energy of the products is greater than the energy of the reactants. Hence, this is considered as a type of endothermic reaction.

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Solid sodium iodide is slowly added to a solution that is 0.0050 M Pb 2+ and 0.0050 M Ag +. [K sp (PbI 2) = 1.4 × 10 –8; K sp (A
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Answer:

[Ag⁺] = 5.0x10⁻¹⁴M

Explanation:

The product solubility constant, Ksp, of the insoluble salts PbI₂ and AgI is defined as follows:

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The PbI₂ <em>just begin to precipitate when the product  [Pb²⁺] [I⁻]² = 1.4x10⁻⁸</em>

<em />

As the initial [Pb²⁺] = 0.0050M:

[Pb²⁺] [I⁻]² = 1.4x10⁻⁸

[0.0050] [I⁻]² = 1.4x10⁻⁸

[I⁻]² = 1.4x10⁻⁸ / 0.0050

[I⁻]² = 2.8x10⁻⁶

<h3>[I⁻] = 1.67x10⁻³</h3><h3 />

So, as the [I⁻] concentration is also in the expression of Ksp of AgI and you know concentration in solution of I⁻ = 1.67x10⁻³M:

[Ag⁺] [I⁻] = 8.3x10⁻¹⁷

[Ag⁺] [1.67x10⁻³] = 8.3x10⁻¹⁷

<h3>[Ag⁺] = 5.0x10⁻¹⁴M</h3>

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