Answer:
i would assume its A
Step-by-step explanation:
Answer:
Below in bold.
Step-by-step explanation:
1) as ABCD is a rhombuc AC bisects < BAD and < BCD .
Therefore < CAD = 1/2 * 104 = 52 degrees.
2) < ACG = < ADC + < CAD ( External angle of triangle theorem)
Therfore < ACG = 76 + 52 = 128 degrees.
A.
the starting point is where t=0
d(0)=-16(0)^2+96(0)+112
D(0)=112
started from 112 feet
b. max height is vertex
for
y=ax^2+bx+c
the x value of the vertex is -b/2a
so
D(t)=-16t^2+96t+112
t value of vertex is -96/(2*-16)=3
it reaches after 3 seconds
C. simpliy evaluate D(t) for t=3
D(3)=-16(3)^2+96(3)+112
D(3)=-16(9)+288+112
D(3)=-144+400
D(3)=256
max height is 256ft
