Answer:
4.408 m/s, 4.102 m/s, 4.026 m/s
Explanation:
The question is incomplete. The text of the original question states:
A race car moves such that its position fits the relationship
:
where x is measured in meters and t in seconds. Determine the instantaneous velocity of the car at t = 4.7 s, using time intervals of 0.40 s, 0.20 s, and 0.10 s.
We can find the instantanoues velocity of the car at any time t by calculating the derivative of the position, so we find:
And now we just need to substitute t=0.40 s, 0.20 s, and 0.10 s to find the corresponding instantaneous velocity:
Answer:
light in the UV range.
Explanation:
Noble gases and halogens can combine to form lasers called Excimer, for this to happen the noble gas must be ionized with a high voltage discharge, thus forming a molecule of the type
noble gas (X) + halogen (H) → XH
This molecule is highly unstable and decomposes within a few nanoseconds, emitting light in the UV range.
T = 27° C = 27 + 273 = 300 K
Bolzmann constant: k b = 1.38065 · 10^(-22) J/K
K = 3/2 kb T
K = 3/2 · 1.38065 · 10^(-22) J/K · 300 K = 6.212925 · 10^(-20) J
Answer:
D
Explanation:
It says constant positive linear acceleration, which means that the velocity increases at a constant rate.