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Andrej [43]
4 years ago
13

A calcium bromide compound is represented by which formula?

Physics
2 answers:
Westkost [7]4 years ago
6 0

option D) CaBr2

hope this helps

ipn [44]4 years ago
4 0

Answer:

Calcium bromide is the name for compounds with the chemical formula CaBr2(H2O)x.

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When the mass of a body is constant, then its acceleration is directly proportional to the force acting on it. When the force ac
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Answer:

True

Explanation:

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A rocket takes off from Earth's surface, accelerating straight up at 47.2 m/s2. Calculate the normal force (in N) acting on an a
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Answer:

Approximately 4.61\times 10^{3}\; {\rm N} upwards (assuming that g = 9.81\; {\rm m\cdot s^{-2}}.)

Explanation:

External forces on this astronaut:

  • Weight (gravitational attraction) from the earth (downwards,) and
  • Normal force from the floor (upwards.)

Let (\text{normal force}) denote the magnitude of the normal force on this astronaut from the floor. Since the direction of the normal force is opposite to the direction of the gravitational attraction, the magnitude of the net force on this astronaut would be:

\begin{aligned}(\text{net force}) &= (\text{normal force}) - (\text{weight})\end{aligned}.

Let m denote the mass of this astronaut. The magnitude of the gravitational attraction on this astronaut would be (\text{weight}) = m\, g.

Let a denote the acceleration of this astronaut. The magnitude of the net force on this astronaut would be (\text{net force}) = m\, a.

Rearrange \begin{aligned}(\text{net force}) &= (\text{normal force}) - (\text{weight})\end{aligned} to obtain an expression for the magnitude of the normal force on this astronaut:

\begin{aligned}(\text{normal force}) &= (\text{net force}) + (\text{weight}) \\ &= m\, a + m\, g \\ &= m\, (a + g) \\ &= 80.9\; {\rm kg} \times (47.2\; {\rm m\cdot s^{-2}} + 9.81\; {\rm m\cdot s^{-2}}) \\ &\approx 4.61 \times 10^{3}\; {\rm N}\end{aligned}.

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2 years ago
If I fell asleep at 9:42 pm and woke up at 10:06 am. What was the total hours of sleep I got?
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Answer:

11 hours and 24 minutes total of sleep. Nice.

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Since its going from pm to am, We have to go past 12 to 1 and go to 9 hours am, then add 42 by 24 minutes to get to the 6 minutes past 10.

#teamtrees #WAP (Water And Plant)

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The force of ___ acts between all objects
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gravity is the force that acts between all objects

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A sample of 20.0 moles of a monatomic ideal gas (γ = 1.67) undergoes an adiabatic process. The initial pressure is and the initi
Alexeev081 [22]
There are some missing data in the text of the exercise. Here the complete text:
"<span>A sample of 20.0 moles of a monatomic ideal gas (γ = 1.67) undergoes an adiabatic process. The initial pressure is 400kPa and the initial temperature is 450K. The final temperature of the gas is 320K. What is the final volume of the gas? Let the ideal-gas constant R = 8.314 J/(mol • K). "

Solution:

First, we can find the initial volume of the gas, by using the ideal gas law:
</span>pV=nRT
<span>where 
p is the pressure
V the volume
n the number of moles
R the gas constant
T the absolute temperature

Using the initial data of the gas, we can find its initial volume:
</span>V_i =  \frac{nRT_i}{p_i} = \frac{(20.0 mol)(8.31 J/molK)(450 K)}{4 \cdot 10^5 Pa} =0.187 m^3
<span>
Then the gas undergoes an adiabatic process. For an adiabatic transformation, the following relationship between volume and temperature can be used:
</span>TV^{\gamma-1} = cost.
<span>where </span>\gamma=1.67 for a monoatomic gas as in this exercise. The previous relationship can be also written as
T_i V_i^{\gamma-1} = T_f V_f^{\gamma-1}
where i labels the initial conditions and f the final conditions. Re-arranging the equation and using the data of the problem, we can find the final volume of the gas:
V_f = V_i  \sqrt[\gamma-1]{ \frac{T_i}{T_f} }=(0.187 m^3) \sqrt[0.67]{ \frac{450 K}{320 K} }=0.310 m^3 = 310 L
So, the final volume of the gas is 310 L.
5 0
3 years ago
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