If it is just a reseach investigatory project, you could monitor it by using different variables (controlled), acurate measuring devices and camera for documentations
Let's just assume that you throw the ball with an initial speed of 2 m/s instead of dropping it like free falling.
a=9.81 m/s^2
Vi= 2 m/s
t= 3 x
we use the formula
d = (Vi)(t) + (1/2)(a)(t)^2
d= (2)(3) + (1/2)(9.81)(9)
d=50.145 m
Answer:

Explanation:
The potential energy (PE) we are looking here is gravitational potential energy (GPE).
GPE= mgh,
where m is the mass of an object,
g is the gravitational field strength
h is the height of the object
KE= ½mv²,
where m is the mass and v is the velocity
loss in GPE= gain in KE
mgh= ½mv²
gh= ½v² (<em>divide by m throughout</em>)
Assuming that the object is on earth, then g= 10N/Kg
½v²= 10h (<em>substitute g=10</em>)
v²= 20h (<em>×2 on both sides</em>)
v= √20h (<em>square root both sides</em>)
C. Both mass and velocity increases