Answer:
2065.005 m/s²
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
g = Acceleration due to gravity = 9.81 m/s²

Now H-h = 42.3 - 0.2 = 42.1 cm = 0.421 m
The final velocity will be the initial velocity

Acceleration of the frog is 2065.005 m/s²
Answer:
The greatest acceleration the man can give the airplane is 0.0059 m/s².
Explanation:
Given that,
Mass of man = 85 kg
Mass of airplane = 109000 kg
Distance = 9.08
Coefficient of static friction = 0.77
We need to calculate the greatest friction force
Using formula of friction

Where, m = mass of man
g = acceleration due to gravity
Put the value into the formula


We need to calculate the acceleration
Using formula of newton's second law


Put the value into the formula


Hence, The greatest acceleration the man can give the airplane is 0.0059 m/s².
Answer:
Technician A
Explanation:
If Technician B was correct, and the master cylinder is defective - then no braking action would occur.
This is not true however, as some breaking action eventually occurs, meaning it must be out of adjustment.
The only correct statement on the list is choice-A./