Work done = 0.5*m*[(v2)^2 - (v1)^2]
where m is mass,
v2 and v1 are the velocities.
Given that m = 1.50 x 10^3 kg, v2 = -15 m/s (decelerates), v1 = 25 kg,
Work done = 0.5 * 1.50 x 10^3 * ((-15)^2 - 25^2) = 3 x 10^5 joules
Just ignore the negative value for the final result because work is a scalar quantity.
Answer:
B. False
Explanation:
Not all objects near the earths surface - regardless of size and weight - have the same force of gravity on them.
The percent complete is calculated by dividing the quantity of material progressed at a point in time by the total quantity required for the project. The resulting percent is multiplied by the current agreed committed value of the material item to obtain the VOWD for that item.
Circular Motion does occur on earth, so yes, true
The resistance of the cylindrical wire is 
.
Here 
is the resistance, 
is the length of the wire and 
is the area of
cross section. Since the wire is cylindrical 
.
Comparing two wires,
Dividing the above 2 equations,
Since 
The above ratio is
We also have,
The current through the Silver wire will be 4.23 times the current through the original wire.
