Answer:
2.1 × 10⁻¹ M
2.0 × 10⁻¹ m
Explanation:
Molarity
The molar mass of aniline (solute) is 93.13 g/mol. The moles corresponding to 3.9 g are:
3.9 g × (1 mol/93.13 g) = 0.042 mol
The volume of the solution is 200 mL (0.200 L). The molarity of aniline is:
M = 0.042 mol/0.200 L = 0.21 M = 2.1 × 10⁻¹ M
Molality
The moles of solute are 0.042 mol.
The density of the solvent is 1.05 g/mL. The mass corresponding to 200 mL is:
200 mL × 1.05 g/mL = 210 g = 0.210 kg
The molality of aniline is:
m = 0.042 mol/0.210 kg = 0.20 m = 2.0 × 10⁻¹ m
Answer:
The order is: electron, carbon, water, glucose, glycogen.
Explanation:
The electron is a negatively charged subatomic particle and is therefore the smallest.
Carbon is a chemical element, which belongs to the group-14 of periodic table and has atomic number 6.
Water is a odorless, almost colorless and tasteless chemical compound which is necessary for all the known living form. The chemical formula is H2O and it is composed of 2 hydrogen atoms and one oxygen atom.
Glucose is a monosaccharide sugar and a type of simple carbohydrate. The chemical formula is C6H12O6 and is composed of 6 carbon atoms, 6 oxygen atoms and 12 hydrogen atoms.
Glycogen is a branched polysaccharide molecule, which is composed of multiple monomeric glucose units. Therefore, it is the largest.
<u>Therefore, the increasing order is: electron, carbon, water, glucose, glycogen.</u>
Answer:
I believe the answer The case study was influenced by bias, and led to incorrect conclusions being drawn. plz correct me if I am wrong
Explanation:
Answer:
The result is a superposition which is twice the amplitude of each input wave. Φ = π means the two waves are completely OUT OF PHASE, and so add completely destructively. The result is a superposition which has no amplitude at all.
Explanation:
The result is a superposition which is twice the amplitude of each input wave. Φ = π means the two waves are completely OUT OF PHASE, and so add completely destructively. The result is a superposition which has no amplitude at all.
Using the answer from the first part, we know that 2.957 moles of bismuth have formed. Moreover, the molar ratio between bismuth and carbon monoxide is:
2 : 3
Using the method of ratios,
2 : 3
2.957 : CO
CO = (3 * 2.957) / 2
CO = 4.4355
4.436 moles of carbon monoxide will be formed