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blsea [12.9K]
3 years ago
12

Please help me, I am confused on this.

Chemistry
2 answers:
weeeeeb [17]3 years ago
4 0

Answer:

The First choice is correct

Explanation:

That is the closest example of what is shown

Sophie [7]3 years ago
4 0

Answer:

A

Explanation:

Makes the most scene

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How many moles of NH3 can you make from 6.20 moles of N2?
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Which of the following is an endothermic reaction?
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The answer is the reaction ins a cold pack
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Identify the effect of increasing acidity on the solubility of the given compounds.
Ilia_Sergeevich [38]

All the given compounds are basic on acidifying their solubility increases.

<u>Explanation:</u>

  • C a_{3}\left(P O_{4}\right)_{2} solubility will increase, since it is basic in nature, on acidifying  solubility increases.
  • F e S being basic on acidification, the solubility increases.
  • M g C O_{3} is alkaline in nature, it gets neutralized and there is no increase in acidity.
  • M g B r_{2} is a salt and it shows no effect on acidification.
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4 0
3 years ago
Determine the empirical formula of a
k0ka [10]

Answer:

AuCl

Explanation:

Given parameters:

Mass of Gold  = 2.6444g

Mass of Chlorine  = 0.476g

Unknown:

Empirical formula  = ?

Solution:

Empirical formula is the simplest formula of a compound. Here is the way of determining this formula.

Elements                                     Au                                             Cl

Mass                                         2.6444                                     0.476

Molar mass                                 197                                          35.5

Number of moles                  2.6444/197                                 0.476/35.5

                                                 0.013                                           0.013

Divide by the

smallest                                 0.013/0.013                                 0.013/0.013

                                                       1                                                   1

The empirical formula of the compound is AuCl

3 0
2 years ago
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