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tensa zangetsu [6.8K]
2 years ago
14

Two 2 kg masses is placed at either end of a rod that has a mass of .5 kg and a length of 3 m. What is the moment of inertia if

the system it is rotated about (a) one end of the rod and (b) the center of the rod?
Physics
1 answer:
sergij07 [2.7K]2 years ago
7 0

Explanation:

a) I=\displaystyle \sum_{i}m_ir_i^2

where r_i is the distance of the mass m_i from the axis of rotation. When the axis of rotation is placed at the end of the rod, the moment of inertia is due only to one mass. Therefore,

I= mr^2 = (2\:kg)(3\:m)^2 = 18\:kg-m^2

b) When the axis of rotation is placed on the center of the rod, the moment is due to both masses and the radius r is 1.5 m. Therefore,

\displaystyle I= \sum_{i}m_ir_i^2 = 2(2\:kg)(1.5\:m)^2 = 9\:kg-m^2

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If all this energy is added to 50 kg of water (the amount of water in a 165-lb person) at 37 ∘C, what is the final state of the
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Q_{water} = 50 \times \times 4180 \times (100-37)\\= 1.132 \times 10^7 \ J

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2 years ago
A small plastic ball with a mass of 7.00 10-3 kg and with a charge of +0.155 µC is suspended from an insulating thread and hangs
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Answer:

the magnitude of the charge Q on each plate is 3.053 *10^{-8} \ C

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