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Pie
3 years ago
5

Suppose these waves represent the sound of a siren on a passing ambulance. Which wave represents the sound of the siren after it

has passed you? Explain your answer.
The wave A has a higher frequency and wave B has a lower frequency.

I REALLY need help. Please.
Physics
2 answers:
sergeinik [125]3 years ago
4 0
The answer is wave B has a lower frequency.  Suppose these waves represent the sound of a siren on a passing ambulance. Wave B (lower frequency) represents the sound of the siren after it has passed you.  The ambulance moving towards the observer produces a higher than normal frequency, and the ambulance moving away produces a lower than normal frequency.
sergey [27]3 years ago
4 0

Answer:

The correct answer is "wave B has a lower frequency."

Explanation:

The Doppler effect is defined as the change in apparent frequency of a wave produced by the relative movement of the source with respect to its observer. In other words, this effect is the change in the perceived frequency of any wave movement when the sender and the receiver, or observer, move relative to each other.

This is the effect that occurs in this case. And it is explained as follows: When the ambulance approaches the observer, the wave "compresses", that is, the wavelength is short, the frequency high and, therefore, the tone of the perceived sound will be sharp. On the other hand, when the ambulance moves away from the observer, the wave "decompresses", that is, the wavelength is long and the frequency low.

Then the correct answer is "wave B has a lower frequency."

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a bus is moving at 22m/s [E] for 12s. Then the bus driver slows down at 1.2m/s2 [W] until the bus stops. Determine the total dis
KatRina [158]
The total displacement is equal to the total distance. For the east or E direction, the distance is determined using the equation:

d = vt = (22 m/s)(12 s) = 264 m

For the west or W direction, we use the equations:
a = (v - v₀)/t
d = v₀t + 0.5at²

Because the object slows down, the acceleration is negative. So,
-1.2 m/s² = (0 m/s - 22 m/s)/t
t = 18.33 seconds
d = (22 m/s)(18.33 s) + 0.5(-1.2 m/s²)(18.33 s)²
d = 201.67 m

Thus,
Total Displacement = 264 m +  201.67 m = 465.67 or  approximately 4.7×10² m.
7 0
2 years ago
The fulcrum of a first-class lever divides its 9.0 m arm into two sections—a 6.0 m arm and a 3.0 m arm. You place a rock weighin
nexus9112 [7]
For balancing the lever, force on both the sides shall be equal. so,
Force on 3 m end = m × a = 3 × 98.1 = 294.3

Now, on 6 m end, it would be: = 294.3/6 = 49.05
After rounding-off to the nearest hundredth value, it would be: 49 N

Finally, Option A would be your correct answer.

Hope this helps!
6 0
2 years ago
I need the answer right now pls help me
yaroslaw [1]

The AREA of the shaded region is the moving object's displacement.

7 0
3 years ago
As the space shuttle orbits the Earth, the shuttle and the astronauts
morpeh [17]
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2 years ago
DETERMINE THE LAUNCH ELEVATION AND MAXIMUM RANGE: The test vehicle should obtain a burnout velocity of 7200 m/s at 180 km altitu
fenix001 [56]

Answer:

Flight path angle= 15.12°, maximum range= 5.29× 10*6 km

Explanation:

u= 7200m/s, H= 180km= 180000m

Recall that

Maximum height, H= (u*2sin*2∆)/2g

180000= (7200×7200sin*2∆)/2×9.8

(18000×2×98)/7200×7200= sin*2∆

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Maximum range, R= u*2/g

(7200×7200)/9.8

= 5289795.92km

= 5.29× 10*6 km

8 0
3 years ago
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