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3 years ago

7

two identical-looking, large, round balls are placed in front of you. one is filled with feathers and the other is filled with s

and. wothout lifting the balls, how could you use newton's first law to distinguish between them?

1 answer:

Lelu [443]3 years ago

3 0

If you apply a little bit of force, one will move easier than the other since it is lighter.

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A red blood cell is 7 x 10-6 m in size. This means it is 7 __________ in size. What unit completes the sentence?

aalyn [17]

If a red blood cell is 7 x $10^-^6$ m in size, it means that such a cell is 7 microns or micrometer in size. The unit that completes the sentence will, thus, be microns or micrometer.

According to international system of measurement:

$10^{-1}$ m = decimeter

$10^{-2}$ m = centimeter

$10^{-3}$ m = millimeter
$10^{-6}$ m = micrometer or micron
$10^{-9}$ m = nanometer

Thus, a measurement of 7 x $10^-^6$ m is the same is 7 micons or 7 micrometer.

More on metric conversion can be found here: brainly.com/question/17767575

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2 years ago

The intensity of light depends on the amount of *blank blank*

babymother [125]

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3 years ago

A point moves on the x-axis in such a way that its velocity at time t (t > 0) is given by v=ln t/t . At what value of t does

Olenka [21]

Answer:

Explanation:

Given

Velocity of point is given by $v=\frac{\ln t}{t}$

To get maximum or minimum velocity differentiate v w.r.t t

$\frac{\mathrm{d} v}{\mathrm{d} t}=\frac{\frac{1}{t}\times t-1\times \ln(t)}{t^2}$

so $1-\ln (t)$ should be equal to zero

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i.e. $t=2.718\ s$

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3 years ago

Why are plane mirrors and convex mirrors unable to form real images

Schach [20]

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4 years ago

A 5.75 × 107 kg battle ship originally at rest fires a 1100-kg artillery shell horizontally with a velocity of 550 m/s. show ans

prohojiy [21]

Answer:

-0.01052 m/s

Explanation:

M = mass of ship = $5.75\times 10^7\ kg$

m = mass of shell = 1100 kg

v = velocity of shell = 550 m/s

u = recoil velocity of ship

As linear momentum is conserved

$(M - m)u=-mv\\\Rightarrow u=-\frac{mv}{M - m}\\\Rightarrow u=-\frac{1100\times 550}{5.75\times 10^7+1100}\\\Rightarrow u=-0.01052\ m/s$

The recoil velocity of the ship taking the firing direction to be the positive direction is -0.01052 m/s

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3 years ago