Answer:
increases by a factor of 6.
Explanation:
Let us assume that the initial cross sectional area of the pipe is A m² while the initial velocity of the water is V m/s², hence the flow rate of the water is:
Initial flow rate = area * velocity = A * V = AV m³/s
The water speed doubles (2V m/s) and the cross-sectional area of the pipe triples (3A m²), hence the volume flow rate becomes:
Final flow rate = 2V * 3A = 6AV m³/s = 6 * initial flow rate
Hence, the volume flow rate of the water passing through it increases by a factor of 6.
Answer:
Communication is simply the act of transferring information from one place, person or group to another. Every communication involves (at least) one sender, a message and a recipient.
Explanation:
Answer:
Enthalpy at outlet=284.44 KJ
Explanation:
![m_1=1 Kg/s,m_2=1.5 Kg/s,m_3=22 Kg/s](https://tex.z-dn.net/?f=m_1%3D1%20Kg%2Fs%2Cm_2%3D1.5%20Kg%2Fs%2Cm_3%3D22%20Kg%2Fs)
![h_1=100 KJ/Kg,h_2=120 KJ/Kg,h_3=500 KJ/Kg](https://tex.z-dn.net/?f=h_1%3D100%20KJ%2FKg%2Ch_2%3D120%20KJ%2FKg%2Ch_3%3D500%20KJ%2FKg)
We need to Find enthalpy of outlet.
Lets take the outlet mass m and outlet enthalpy h.
So from mass conservation
![m_1+m_2+m_3=m](https://tex.z-dn.net/?f=m_1%2Bm_2%2Bm_3%3Dm)
m=1+1.5+2 Kg/s
m=4.5 Kg/s
Now from energy conservation
![m_1h_1+m_2h_2+m_3h_3=mh](https://tex.z-dn.net/?f=m_1h_1%2Bm_2h_2%2Bm_3h_3%3Dmh)
By putting the values
![1\times 100+1.5\times 120+2\times 500=4.5\times h](https://tex.z-dn.net/?f=1%5Ctimes%20100%2B1.5%5Ctimes%20120%2B2%5Ctimes%20500%3D4.5%5Ctimes%20h)
So h=284.44 KJ
Answer:
(a) The magnitude of force is 116.6 lb, as exerted by the rod CD
(b) The reaction at A is (-72.7j-38.1k) lb and at B it is (37.5j) lb.
Explanation:
Step by step working is shown in the images attached herewith.
For this given system, the coordinates are the following:
A(0, 0, 0)
B(26, 0, 0)
And the value of angle alpha is 20.95°
Hope that answers the question, have a great day!