Answer:
The thrust of the engine calculated using the cold air is 34227.35 N
Explanation:
For the turbofan engine, firstly the overall mass flow rate is considered. The mass flow rate is given as
Here
- ρ is the density which is given as
- P is the pressure of air at 5500 m from the ISA whose value is 50506.80 Pa
- R is the gas constant whose value is 286.9 J/kg.K
- T is the temperature of the inlet which is given as 253 K
- A is the cross-sectional area of the inlet which is given by using the diameter of 2.0 m
- V_a is the velocity of the aircraft which is given as 250 m/s
So the equation becomes
Now in order to find the flow from the fan, the Bypass ratio is used.
Here BPR is given as 8 so the equation becomes
Now the exit velocity is calculated using the total energy balance which is given as below:
Here
- h_4 and h_5 are the enthalpies at point 4 and 5 which could be rewritten as and respectively.
- The value of T_4 is the inlet temperature which is 253 K
- The value of T_5 is the outlet temperature which is 233K
- The value of c_p is constant which is 1005 J/kgK
- V_a is the inlet velocity which is 250 m/s
- V_e is the outlet velocity that is to be calculated.
So the equation becomes
Rearranging the equation gives
Now using the cold air approach, the thrust is given as follows
So the thrust of the engine calculated using the cold air is 34227.35 N
Solar time for
North Platte is 13.02
Boise is 13.02
Eastern daylight time is 12.48
Central daylight is 12.06
<u>Explanation:</u>
- 6 hours "central standard time" is the standard time zone. The saving time of daylight is + 1 hour. current time zone is the 5 hours central daylight time.
- 7 hours is the mountain standard time. The saving time of daylight is + 1 hour. current time zone is the 6 hours central daylight time.
- 5 hours is the eastern daylight time. The time shifts to +1 hour forwarded to eastern daylight zone and GMT is behind 4 hours.
- 5 hours is the central daylight time. The GMT is behind 5 hours during summer season
Answer:
7,217*10^28 atoms/m^3
Explanation:
- Metal: Vanadium
- Density: 6.1 g/cm^3
- Molecuar weight: 50,9 g/mol
The Avogadro's Number, 6,022*10^23, is the number of atoms in one mole of any substance. To calculate the number of atoms in one cubic meter of vanadium we write:
1m^3*(100^3 cm^3/1 m^3)*(6,1 g/1 cm^3)*(1 mol/50,9g)*(6,022*10^23 atoms/1 mol)=7,217*10^28 atoms
Therefore, for vanadium we have 7,217*10^28 atoms/m^3
100: D, third law of motion
101: D, second law of motion