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Vesnalui [34]
3 years ago
8

Two AAA-size lithium batteries are connected in series in a flashlight. Each battery has 3.5 volt and 4- Amp-hour capacity. If t

he flashlight is connected to a light bulb with 10 Ohms resistance. How long does it take to drain the batteries?
Engineering
1 answer:
mafiozo [28]3 years ago
7 0

Answer:

t= 9.79 hr

Explanation:

Given that

V= 3.5 V

Capacity= 4 Amp-hour

We know that

V= IR

V= Voltage

I =Current

R=Resistance

V = I R

The total voltage on the  batteries will be  2 V

2 x 3.5 = I x 10

I= 0.7 A

We know that Power P

P = V I

P = 0.7 x 7

P =4.9 W

4 A.h and 12 volt power supply = 4 x 12 = 48 W.hr

So time of drain t

4.9 t = 48

t= 9.79 hr

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In an experiment, the local heat transfer over a flat plate were correlated in the form of local Nusselt number as expressed by
zvonat [6]

Answer:

R= 1.25

Explanation:

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Replacing the values

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Where V is the velocity of the fluid and \upsilon is the Kinematic viscosity

Then replacing we have

h_x=0.035(\frac{Vx}{\upsilon})^{0.8}Pr^{1/3}kx^{-1}

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h_x=Ax^{-0.2}

<em>*Note that A is just a 'summary' of all of that constat there.</em>

<em>That is A=0.035(\frac{V}{\upsilon})^{0.8}Pr^{1/3}k</em>

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R = \frac{h}{h_L}\\R= \frac{1.25Al^{-0.2}}{AL^{-0.2}}\\R= 1.25

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2 years ago
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