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Lisa [10]
3 years ago
11

This search compares the target value with the middle element in the collection, then ignores the half of the collection in whic

h the target cannot exist a) Linear b) Exponential c) Interpolation d) Binary
Engineering
1 answer:
love history [14]3 years ago
7 0

Answer:

d) Binary

Explanation:

Binary search is a search algorithm that finds the position of a value in an ordered array. It compares the value with the element in the middle of the array, if they are not equal, half in which the value cannot be eliminated and the search continues in the remaining half until the value is found.

You might be interested in
A power plant operates on a regenerative vapor power cycle with one open feedwater heater. Steam enters the first turbine stage
ivolga24 [154]

Answer:

a. 46.15%

b. 261.73 kg/s

c. 54.79 kW/K

Explanation:

a. State 1

The parameters given are;

T₁ = 560°C

P₁ = 12 MPa = 120 bar

Therefore;

h₁ = 3507.41 kJ/kg,  s₁ = 6.6864 kJ/(kg·K)

State 2

p₂ = 1 MPa = 10 bar

s₂ = s₁ = 6.6864 kJ/(kg·K)

h₂ = (6.6864 - 6.6426)÷(6.6955 - 6.6426)×(2828.27 - 2803.52) + 2803.52

= (0.0438 ÷ 0.0529) × 24.75 = 2824.01 kJ/kg

State 3

p₃ = 6 kPa = 0.06 bar

s₃ = s₁ = 6.6864 kJ/(kg·K)

sg = 8.3291 kJ/(kg·K)

sf = 0.52087 kJ/(kg·K)

x = s₃/sfg = (6.6864- 0.52087)/(8.3291  - 0.52087) = 0.7896

(h₃ - 151.494)/2415.17 = 0.7896

∴ h₃ = 2058.56 kJ/kg

State 4

Saturated liquid state

p₄ = 0.06 bar= 6000 Pa, h₄ = 151.494 kJ/kg, s₄ = 0.52087 kJ/(kg·K)

State 5

Open feed-water heater

p₅ = p₂ =  1 MPa = 10 bar = 1000000 Pa

s₄ = s₅ = 0.52087 kJ/(kg·K)

h₅ = h₄ + work done by the pump on the saturated liquid

∴ h₅ = h₄ + v₄ × (p₅ - p₄)

h₅ = 151.494 + 0.00100645 × (1000000 - 6000)/1000 = 152.4944113 kJ/kg

Step 6

Saturated liquid state

p₆ = 1 MPa = 10 bar

h₆ = 762.683 kJ/kg

s₆ = 2.1384 kJ/(kg·K)

v₆ = 0.00112723 m³/kg

Step 7

p₇ = p₁ = 12 MPa = 120 bar

s₇ = s₆ = 2.1384 kJ/(kg·K)

h₇ = h₆ + v₆ × (p₇ - p₆)

h₇ = 762.683  + 0.00112723 * (12 - 1) * 1000 = 775.08253 kJ/kg

The fraction of flow extracted at the second stage, y, is given as follows

y = \dfrac{762.683 - 152.4944113 }{2824.01 - 152.4944113 } = 0.2284

The turbine control volume is given as follows;

\dfrac{\dot{W_t}}{\dot{m_{1}}} = \left (h_{1} - h_{2}  \right ) + \left (1 - y  \right )\left (h_{2} - h_{3}  \right )

= (3507.41  - 2824.01) + (1 - 0.22840)*(2824.01 - 2058.56) = 1274.02122 kJ/kg

For the pumps, we have;

\dfrac{\dot{W_p}}{\dot{m_{1}}} = \left (h_{7} - h_{6}  \right ) + \left (1 - y  \right )\left (h_{5} - h_{4}  \right )

= (775.08253 - 762.683) + (1 - 0.22840)*(152.4944113 -  151.494)

= 13.17 kJ/kg

For the working fluid that flows through the steam generator, we have;

\dfrac{\dot{Q_{in}}}{\dot{m_{1}}} = \left (h_{1} - h_{7}  \right )

= 3507.41 - 775.08253 = 2732.32747 kJ/kg

The thermal efficiency, η, is given as follows;

\eta = \dfrac{\dfrac{\dot{W_t}}{\dot{m_{1}}} -\dfrac{\dot{W_p}}{\dot{m_{1}}}}{\dfrac{\dot{Q_{in}}}{\dot{m_{1}}}}

η = (1274.02122 - 13.17)/2732.32747 = 0.4615 which is 46.15%

(762.683 - 152.4944113)/(2824.01 - 152.4944113)

b. The mass flow rate, \dot{m_{1}}, into the first turbine stage is given as follows;

\dot{m_{1}} = \dfrac{\dot{W_{cycle}}}{\dfrac{\dot{W_t}}{\dot{m_{1}}} -\dfrac{\dot{W_p}}{\dot{m_{1}}}}

\dot{m_{1}} = 330 *1000/(1274.02122 - 13.17) = 261.73 kg/s

c. From the entropy rate balance of the steady state form, we have;

\dot{\sigma }_{cv} = \sum_{e}^{}\dot{m}_{e}s_{e} - \sum_{i}^{}\dot{m}_{i}s_{i} = \dot{m}_{6}s_{6} - \dot{m}_{2}s_{2} - \dot{m}_{5}s_{5}

\dot{\sigma }_{cv} = \dot{m}_{6} \left [s_{6} - ys_{2} - (1 - y)s_{5}  \right ]

= 261.73 * (2.1384 - 0.2284*6.6864 - (1 - 0.2284)*0.52087 = 54.79 kW/K

4 0
3 years ago
A fixed mass of saturated water vapor at 400 kpa is isothermally cooled until it is a saturated liquid. Calculate the amount of
Kazeer [188]
This is the explanation

6 0
3 years ago
Explain the benefits of reading A vocabulary section at the beginning of a text
Zinaida [17]

Answer: Deatiled information

Explanation:

It helps the reader organize and sort information in the text. It provides detailed information about the content of the text. It prepares readers to look for new vocabulary as they read.

3 0
3 years ago
Read 2 more answers
A solid steel shaft has to transmit 100 kW at 160 RPM. Taking allowable shear stress at 70 Mpa, find the suitable diameter of th
MA_775_DIABLO [31]

Answer:

The diameter of the shaft is 80.5 mm.

Explanation:

Torsion equation is applied for the diameter of the solid shaft.

Step1

Given:

Power of the shaft is 100 kw.

Revolution per minute is 160 RPM.

Allowable shear stress is 70 Mpa.

Maximum torque is 20% more than the mean torque.  

Step2

Mean torque is calculated as follows:

P=T\omega

P=T(\frac{2\pi N}{60})

100\times 1000=T(\frac{2\pi 160}{60})

T=5968.31 N-m

Step3

Maximum torque is calculated as follows:

T_{max}=(1+\frac{20}{100})T

T_{max}=1.2T

T_{max}=1.2\times 5968.31

T_{max}=7161.97 N-m

Step4

Apply torsional equation for diameter of shaft as follows:

\tau _{max}=\frac{T_{max}}{\frac{\pi d^{3}}{16}}

70\times 10^{6}=\frac{7161.97}{\frac{\pi d^{3}}{16}}

d^{3}=5.211\times 10^{-4}

d=0.0805 m

or,

d=80.5 mm

Thus, the diameter of the shaft is 80.5 mm.

7 0
3 years ago
Bryan a project manager and his team have been assigned a new project. The team members have already started working on their as
Vedmedyk [2.9K]

Answer:

there teams management is good

4 0
3 years ago
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