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2 years ago

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This search compares the target value with the middle element in the collection, then ignores the half of the collection in whic

h the target cannot exist a) Linear b) Exponential c) Interpolation d) Binary

1 answer:

love history [14]2 years ago

7 0

Answer:

d) Binary

Explanation:

Binary search is a search algorithm that finds the position of a value in an ordered array. It compares the value with the element in the middle of the array, if they are not equal, half in which the value cannot be eliminated and the search continues in the remaining half until the value is found.

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A cantilever beam AB of length L has fixed support at A and spring support at B.

atroni [7]

The force in the spring will be $F =\dfrac{KPl^3}{3EI}$ .

The deflection of the beam will be $\rho$ = $0.15(\dfrac{KPL^3}{3EI})$

<h3>What is a cantilever beam?</h3>

A rigid, horizontally extending structural member known as a cantilever is supported at only one end. Typically, it extends from a solidly affixed flat vertical surface, such as a wall.

Given that:-

A cantilever beam AB of length L has fixed support at A and spring support at B.
The spring behaves in a linearly elastic manner with stiffness k. If a concentrated load P is applied at B.

The spring force will be calculated as:-

$F = kx$

Deflection will be given by:-

$x = \dfrac{PL^3}{3EI}$

The spring force will be calculated by:-

$F = \dfrac{KPL^3}{3EI}$

The deflection of the beam will be given as:-

$\rho = \dfrac{0.15KPL^3}{3EI}$

Therefore the force in the spring will be $F =\dfrac{KPl^3}{3EI}$ ..The deflection of the beam will be $\rho$ = $0.15(\dfrac{KPL^3}{3EI})$

To know more about Cantilever beam follow

brainly.com/question/16791806

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7 0

1 year ago

Calculate the load, PP, that would cause AA to be displaced 0.01 inches to the right. The wires ABAB and ACAC are A36 steel and

Nataly [62]

Answer:

P = 4.745 kips

Explanation:

Given

ΔL = 0.01 in

E = 29000 KSI

D = 1/2 in

LAB = LAC = L = 12 in

We get the area as follows

A = π*D²/4 = π*(1/2 in)²/4 = (π/16) in²

Then we use the formula

ΔL = P*L/(A*E)

For AB:

ΔL(AB) = PAB*L/(A*E) = PAB*12 in/((π/16) in²*29*10⁶ PSI)

⇒ ΔL(AB) = (2.107*10⁻⁶ in/lbf)*PAB

For AC:

ΔL(AC) = PAC*L/(A*E) = PAC*12 in/((π/16) in²*29*10⁶ PSI)

⇒ ΔL(AC) = (2.107*10⁻⁶ in/lbf)*PAC

Now, we use the condition

ΔL = ΔL(AB)ₓ + ΔL(AC)ₓ = ΔL(AB)*Cos 30° + ΔL(AC)*Cos 30° = 0.01 in

⇒ ΔL = (2.107*10⁻⁶ in/lbf)*PAB*Cos 30°+(2.107*10⁻⁶ in/lbf)*PAC*Cos 30°= 0.01 in

Knowing that PAB*Cos 30°+PAC*Cos 30° = P

we have

(2.107*10⁻⁶ in/lbf)*P = 0.01 in

⇒ P = 4745.11 lb = 4.745 kips

The pic shown can help to understand the question.

5 0

3 years ago

What do you guys like in engineering

Drupady [299]

Answer:

building lol and actually workin

Explanation:

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2 years ago

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Triss [41]

Answer:

2.5 is the required details

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2 years ago

1: A baseball is hit 4 feet above the ground leaves the bat with an initial speed of 98 ft/sec at an angle of 0 45 is caught by

zvonat [6]

Answer:

299.36 feet

Explanation:

$To \ find \ the \ distance \ of \ the \ ball \ from \ the \ home \ plate. \\ \\ From \ the \ given \ information:$

$Height \ h = 4 \ ft$

$Initial \ speed \ V_o = 98 \ ft/s ec$

$The \ angle \ \theta = 45^0$

$Acceleration \ due \ to \ gravity (g)= 32.2 \ ft/s$

$U_x = V_o \ cos 45 = \dfrac{98}{\sqrt{2}}$

$U_y = V_o \ sin 45 = \dfrac{98}{\sqrt{2}}$

So;

$S_y = u_y t - \dfrac{1}{2}gt^2$

$-1 =\dfrac{98}{\sqrt{2}}t - \dfrac{1}{2}*32*1.85t^2$

By solving:

$t_1 = 4.32 \ sec$

Thus;

$horizontal \ distance = U_x t$

$= \dfrac{98}{\sqrt{2}}\times 4.32$

$\mathbf{=299.36 \ feet}$

$\mathbf{Thus \ , the \ distance \ from \ the \ home \ plate \ = \ 299.36 \ feet}$

5 0

2 years ago