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Lisa [10]
3 years ago
11

This search compares the target value with the middle element in the collection, then ignores the half of the collection in whic

h the target cannot exist a) Linear b) Exponential c) Interpolation d) Binary
Engineering
1 answer:
love history [14]3 years ago
7 0

Answer:

d) Binary

Explanation:

Binary search is a search algorithm that finds the position of a value in an ordered array. It compares the value with the element in the middle of the array, if they are not equal, half in which the value cannot be eliminated and the search continues in the remaining half until the value is found.

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A wastewater treatment plant discharges 1.0 m3/s of effluent having an ultimate BOD of 40.0 mg/ L into a stream flowingat 10.0 m
kondaur [170]

Answer:

a) 6.4  mg/l

b) 5.6 mg/l

Explanation:

Given data:

effluent Discharge Q_w = 1.0 m^3.s

Ultimate BOD L_w = 40 mg/l

Discharge of stream Q_r = 10 m^3.s

Stream ultimate BOD L_r = 3  mg/l

a) Ultimate BOD of mixture= \frac{Q_w l_w + Q_r L_r}{Q_w + Q_r}

                                         = \frac{1*40 + 10*3}{10 +1} = 6.4 mg/l

b) utlimate BOD at 10,000 m downstream

t =\frac{distance}{speed} = \frac{10,000}{\frac{Q_r +Q+w}{55}} \times \frac{hr}{3600} \times  \frac{day}{24 hr}

putting Q_r + Q_w = 1+ 10 = 11 m^3/s

t = 0.578  days

we know

L_t = L_o e^{-kt}

L_t = 6.4 \times e^{-0.22 \times 0.578}

L_t = 5.6 mg/l

7 0
3 years ago
The normal stress at gage H calculated in Part 1 includes four components: an axial component due to load P, σaxial, P, a bendin
Degger [83]

Answer:

hello your question has some missing information attached to the answer is the missing component

Answer : αaxial,p = -6.034 ksi ( compressive )

             αbend,p = 19.648 ksi ( tensile )

Explanation:

αaxial, p = \frac{-p}{A}   equation 1

αbend, p = \frac{(P*A)*\frac{d}{2} }{I_{z} } equation 2

P = load = 35 kips

A = area of column = 5.8 in^{2}

d = column cross section depth = 9.5 in

I_{Z} = 55.0 in^{4}

Hence equation 1 becomes

αaxial,p = -35 / 5.8 = - 6.034 ksi ( compressive )

equation 2 becomes

αbend, p = \frac{(35*6.5)(\frac{9.2}{2}) }{55} = + 19.648 ksi ( tensile )

7 0
3 years ago
A hollow pipe is submerged in a stream of water so that the length of the pipe is parallel to the velocity of the water. If the
Arlecino [84]

Answer:

increases by a factor of 6.

Explanation:

Let us assume that the initial cross sectional area of the pipe is A m² while the initial velocity of the water is V m/s², hence the flow rate of the water is:

Initial flow rate = area * velocity = A * V = AV m³/s

The water speed doubles (2V m/s) and the cross-sectional area of the pipe triples (3A m²), hence the volume flow rate becomes:

Final flow rate = 2V * 3A = 6AV m³/s = 6 * initial flow rate

Hence, the volume flow rate of the water passing through it increases by a factor of 6.

8 0
3 years ago
What should you use to turn the water off and open the door?
galina1969 [7]

youn need to use your hands

7 0
3 years ago
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QUESTION ONE Write short answers on the following questions: i. Rainfall depth over a watershed is monitored through six number
Bond [772]

Answer:

identify function of the system unit and its components

4 0
3 years ago
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