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3 years ago

Which statements describe how the Fed responds to high inflation? Check all that apply.

1 answer:

8 0

Answer:
• it charges banks more interest
• it sells more securities
• it decreases the money supply

In response to high inflation, the Fed charges banks more interests and pays the banks less interests. It also sells not securities.

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An industrial load with an operating voltage of 480/0° V is connected to the power system. The load absorbs 120 kW with a laggin

Leni [432]

Answer:

$Q=41.33 KVAR\ \\at\\\ 480 Vrms$

Explanation:

From the question we are told that:

Voltage $V=480/0 \textdegree V$

Power $P=120kW$

Initial Power factor $p.f_1=0.77 lagging$

Final Power factor $p.f_2=0.9 lagging$

Generally the equation for Reactive Power is mathematically given by

Q=P(tan \theta_2-tan \theta_1)

Since

$p.f_1=0.77$

$cos \theta_1 =0.77$

$\theta_1=cos^{-1}0.77$

$\theta_1=39.65 \textdegree$

And

$p.f_2=0.9$

$cos \theta_2 =0.9$

$\theta_2=cos^{-1}0.9$

$\theta_2=25.84 \textdegree$

Therefore

$Q=P(tan 25.84 \textdegree-tan 39.65 \textdegree)$

$Q=120*10^3(tan 25.84 \textdegree-tan 39.65 \textdegree)$

$Q=-41.33VAR$

Therefore

The size of the capacitor in vars that is necessary to raise the power factor to 0.9 lagging is

$Q=41.33 KVAR\ \\at\\\ 480 Vrms$

6 0

3 years ago

The coefficient of performance of a reversible refrigeration cycle is always (a) greater than, (b) less than, (c) equal to the c

bezimeni [28]

Answer:

Option B is correct

Explanation:

Let

Higher temperature = $T_H$

Lower temperature = $T_L$

We know that COP is given by

$COP = \frac{T_L}{T_H-T_L}$

We see that COP is depends only on the temperature difference & Temperature difference is maximum for the Carnot cycle.

Therefore the COP of reversible refrigeration cycle is always less then the COP of an irreversible refrigeration cycle when each operates between the same two thermal reservoirs.

Therefore option B is correct

5 0

3 years ago

The transfer function of a typical tape-drive system is given by

maw [93]

Answer:

the range of K can be said to be : -3.59 < K< 0.35

Explanation:

The transfer function of a typical tape-drive system is given by;

$KG(s) = \dfrac{K(s+4)}{s[s+0.5)(s+1)(s^2+0.4s+4)]}$

calculating the characteristics equation; we have:

1 + KG(s) = 0

$1+ \dfrac{K(s+4)}{s[s+0.5)(s+1)(s^2+0.4s+4)]} = 0$

${s[s+0.5)(s+1)(s^2+0.4s+4)]} +{K(s+4)}= 0$

$s^5 + 1.9 s^4+ 5.1s^3+6.2s^2+ 2s+K(s+4) = 0$

$s^5 + 1.9 s^4+ 5.1s^3+6.2s^2+ (2+K)s+ 4K = 0$

We can compute a Simulation Table for the Routh–Hurwitz stability criterion Table as follows:

$S^5$ 1 5.1 2+ K

$S^4$ 1.9 6.2 4K

$S^3$ 1.83 $\dfrac{1.9 (2+K)-4K}{1.9}$ 0

$S^2$ $\dfrac{11.34-1.9(X)}{1.83}$ 4K 0

S $\dfrac{XY-7.32 \ K}{Y}$ 0 0

$\dfrac{1.9 (2+K)-4K}{1.9} = X$

$\dfrac{11.34-1.9(X)}{1.83}= Y$

We need to understand that in a given stable system; all the elements in the first column is usually greater than zero

So;

11.34 - 1.9(X) > 0

$11.34 - 1.9(\dfrac{3.8+1.9K-4K}{1.9}) > 0$

$11.34 - (3.8 - 2.1K)>0$

7.54 +2.1 K > 0

2.1 K > - 7.54

K > - 7.54/2.1

K > - 3.59

Also

4K >0

K > 0/4

K > 0

Similarly;

XY - 7.32 K > 0

$(\dfrac{3.8+1.9K-4K}{1.9})[11.34 - 1.9(\dfrac{3.8+1.9K-4K}{1.83}) > 7.32 \ K]$

0.54(2.1K+7.54)>7.32 K

11.45 K < 4.07

K < 4.07/11.45

K < 0.35

Thus the range of K can be said to be : -3.59 < K< 0.35

4 0

3 years ago

A particular motor rotates at 3000 revolutions per minute (rpm). What is its speed in rad/sec, and how many seconds does it take

raketka [301]

Answer:

ω=314.15 rad/s.

0.02 s.

Explanation:

Given that

Motor speed ,N= 3000 revolutions per minute

N= 3000 RPM

The speed of the motor in rad/s given as

Now by putting the values in the above equation

ω=314.15 rad/s

Therefore the speed in rad/s will be 314.15 rad/s.

The speed in rev/sec given as

ω= 50 rev/s

It take 1 sec to cover 50 revolutions

That is why to cover 1 revolution it take

$\dfrac{1}{50}=0.02\ s$

5 0

4 years ago

Read 2 more answers

A state of stress that occurs at a point on the free surface of the of a solid body is = 50 MPa σ x , =10 MPa σ y , and = −15 MP

posledela

Answer:

A) 5 MPa , 55 MPa

B) maximum stress = 55 MPa, maximum shear stress = 25 MPa

Explanation:

using the given Data

free surface of a solid body

α $_{x}$ = 50 MPa, α $_{y}$ = 10 MPa , t $_{xy}$ = -15 MPa

attached below is the detailed solution to the question

7 0

4 years ago