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3 years ago

What is the reciprocal of -9/11?

2 answers:

n200080 [17]3 years ago

7 0

The reciprocal of -9/11 is 11/-9. When using the reciprocal you must always flip the fraction. I'll give some examples:
2/3 is 3/2
4/9 is 9/4
1/16 is 16/1
I hope this helps you!

RUDIKE [14]3 years ago

4 0

The reciprocal of a fraction is the same tying flipped so the reciprocal of -9/11 is 11/-9

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Which of the following equations have complex roots?

valkas [14]

Answer:

Step-by-step explanation:

Completing the square: (x+ 7/2)^2 = -2 + 49/4 = 41/4, in the next step you'll be square rooting a positive number so it'll have real roots.

Completing the square: (x+3/2)^2 = -9 + 9/4 = -27/4, you'll next be square rooting a negative number, so it'll have complex roots

Completing the square: (x-5/2)^2 = -1 + 25/4 = 21/4, next you'll square root a positive number, so real roots

Completing the square: (x+7/2)^2 = 2 + 49/4 = 57/4, square root a positive number, so real roots.

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3 years ago

Which statement is true about figures ABCD and A'B'C'D? (1 point)

Vlad [161]

A.statement . They are congruent

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3 years ago

Read 2 more answers

If f(x) = 3x^2 - 4x + 5 and g(x) = 2x^2 + 2, find f(x) – g(x). Answer: x^2 - 4x + 3

Nadusha1986 [10]

Answer:

f(x) – g(x) = x^2 - 4x + 3

Step-by-step explanation:

f(x) = 3x^2 - 4x + 5 and g(x) = 2x^2 + 2,

f(x) – g(x) = 3x^2 - 4x + 5 - ( 2x^2 + 2)

Distribute the minus sign

f(x) – g(x) = 3x^2 - 4x + 5 - 2x^2 - 2

Combine like terms

f(x) – g(x) = x^2 - 4x + 3

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2 years ago

Help please and ill mark you brainliest :)

rodikova [14]

Answer:

n=100+0.05(460)

Step-by-step explanation:

She earns 100 dollars all the time. so its 100+ something

she also earns 5% of the tips, which in that case were 460$

you can repersent that as 0.05(460)

so: 100+0.05(460)

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3 years ago

A builder wants to build the bridge whose cross section is shown in the diagram. Two companies offer simple bids on building the

leva [86]

The length of the bridge is the distance from the beginning to the end.

The distance b between each beam is 9ft.

Let:

$I \to$ I-Beam

$d_I \to$ distance between I beam and the bridge

$b \to$ distance between each I beam

Given that:

$I = \frac 34 ft\\$

$d_I = 3 ft$

$Length = 55ft\ 6in$ --- length of the bridge

From the diagram (see attachment), there are: 6 I-beams.

So, the length of the 6 I-beams is:

$L_1 = 6 \times I$

$L_1 = 6 \times \frac 34$

$L_1 = \frac {18}4$

$L_1 = 4.5ft$

There are 2 I-beams beside the bridge

So, the distance between the 2 I-beams and the bridge is:

$d_1 =2 \times d_I$

$d_1 =2 \times 3ft$

$d_1 =6ft$

There are 5 spaces between the I-beams

So, the length of the total spaces is:

$L_2 = 5 \times b$

$L_2 = 5b$

The total length is:

$Length = L_1 + d_1 + L_2$

So, we have:

$4.5ft + 6ft + 5b = 55ft\ 6in$

Collect like terms

$5b = 55ft\ 6in - 4.5ft - 6ft$

$5b = 44.5ft\ 6in$

Convert inches to feet

$5b = 44.5ft\ + \frac{6}{12}ft$

$5b = 44.5ft\ + 0.5ft$

$5b = 45ft$

Divide both sides by 5

$b = 9ft$

Hence, the distance (b) between each beam is 9ft.