Answer:
198
Step-by-step explanation:
t20=a+19d.......1
t40=a+39d.......2
t2=a+d=2.........3
According to ques,
t40-t20=a+39d-(a+19d)=40
or,20d=40
or,d=2
Now ,putting the value of d in equation 3,we get,
a=0
t100=a+99d
=0+99×2
=198
For a function to be a function there cannot be any x’s repeated. In this case, you’re looking for a function that has an x repeated. The answer is {(1,1),(1,2),(1,3),(1,4)}
7x +33 < 26 isolate the term with a variable by subtracting 33
7x < -7 divide by 7
x < -1
The solution for x is D=-4
