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qwelly [4]
3 years ago
6

Drag the terms to the appropriate blanks to complete the following sentences summarizing the redox reactions of photosynthesis.

Terms may be used once, more than once, or not at all. View Available Hint(s) ResetHelp NADP+ NADPH ATP ADP H2O CO2 O2 G3P 1. In the light reactions, light energy is used to oxidize NADP+ to NADPH. 2. The electrons derived from this oxidation reaction in the light reactions are used to reduce to . 3. The Calvin cycle oxidizes the light-reactions product to . 4. The electrons derived from this oxidation reaction in the Calvin cycle are used to reduce to .
Chemistry
1 answer:
quester [9]3 years ago
5 0
<h3><u>Answer;</u></h3>

1. In the light reactions, light energy is used to oxidize H2O to O2.

2. The electrons derived from this oxidation reaction in the light reactions are used to reduce NADP+ to NADPH.

3. The Calvin cycle oxidizes the light-reactions product NADPH to NADP+.

4. The electrons derived from this oxidation reaction in the Calvin cycle are used to reduce CO2 to G3P.

<h3><u>Explanation;</u></h3>
  • <em><u>In the light reactions, light energy is used to remove electrons from (oxidize) water, producing O2 gas. These electrons are ultimately used to reduce NADP+ to NADPH. </u></em>
  • In the Calvin cycle, NADPH is oxidized back to NADP+ (which returns to the light reactions). The electrons released by the oxidation of NADPH are used to reduce three molecules of CO2 to sugar (G3P), which then exits the Calvin cycle.
  • As ATP and NADPH are used in the Clavin cycle, they produce ADP and NADP+, respectively, which are returned to the light reactions so that more ATP and NADPH can be formed.
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a certain mass of gas occupies 2240 volume at a pressure of 760mkhg and temperature of 320k.find it's new volume if the preddure
natita [175]

The new volume : V₂ =  2454.8 L

<h3>Further explanation</h3>

Given

V₁=2240 L

P₁=760 mmHg

T₁=320 K

P₂=700 mmHg

T₂=323 K

Required

Volume V₂

Solution

Combined gas law :

P₁V₁/T₁=P₂V₂/T₂

Input the value :

760 mmHg x 2240 L /320 K = 700 mmHg x V₂/323 K

V₂=(P₁V₁T₂)/P₂T₁

V₂=(760 x 2240 x 323)/(700 x 320)

V₂ = 2454.8 L

6 0
3 years ago
For the wild type (unmutated) enzyme, you measure a rate of p-nitrophenol release by the change in absorbance at 405 nm (for the
Aleks04 [339]

Answer:

1.2x10⁻⁵M = Concentration of the product released

Explanation:

Lambert-Beer's law states the absorbance of a solution is directly proportional to its concentration. The equation is:

A = E*b*C

<em>Where A is the absotbance of the solution: 0.216</em>

<em>E is the extinction coefficient = 18000M⁻¹cm⁻¹</em>

<em>b is patelength = 1cm</em>

<em>C is concentration of the solution</em>

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Replacing:

0.216 = 18000M⁻¹cm⁻¹*1cm*C

<h3>1.2x10⁻⁵M = Concentration of the product released</h3>
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They are substances that produce ions when they dissolve in water.
stira [4]

Electrolytes are substances that produce ions when they dissolve in water.

What are electrolytes?

When some substances are dissolved in water, they undergo physical or chemical changes, creating ions in solution. These substances form an important class of compounds called electrolytes. Substances that do not release ions when dissolved are called non-electrolytes. A substance is said to be a strong electrolyte if the physical or chemical process that produces ions is inherently 100% efficient (all dissolved compounds produce ions). A solute is said to be a weak electrolyte if only a relatively small portion of the solute undergoes ion production processes.

By measuring the electrical conductivity of aqueous solutions containing substances, substances can be identified as strong, weak, or non-electrolyte. To conduct electricity, a substance must contain free-moving charged species. The best known is the conduction of electricity through metal wires. In this case, the mobile charged unit is the electron.

Therefore, Electrolytes are substances that produce ions when they dissolve in water.

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7 0
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Answer:

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